180 = 65 + (x-5) + x
-65 -65
115 = x - 5 + x
115 = 2x - 5
2x = 120
x = 60
The angle measures are 65, 60, and 55 degrees.
Answer:
1. 34.4°
2. 18.8°
3. 37.7°
4. 36.6°
5. 40.6°
6. 7.5
7. 12.3
8. 14.7
9. 22.0
10. 6.3
Step-by-step explanation:
1. The missing angle is found by the use of the sine.
Sine ∅= opposite/ hypotenuse
=13/23
sin⁻¹(13/23)=34.4°
2. The missing angle is calculated by the use of the tan.
Tan∅=opposite/adjacent
=17/50
Tan⁻¹(17/50)=18.8°
3. The missing angle is calculated by the use of the tan.
Tan∅=opposite/adjacent
=17/22
Tan⁻¹ (17/22) = 37.7°
4. The missing angle is calculated by the use of the tan.
Tan∅=opposite/adjacent
=21/28
Tan⁻¹ (21/28)=36.9°
5. The missing angle is calculated by the use of the tan.
Tan∅=opposite/adjacent
=24/28
Tan⁻¹ (24/28) = 40.6°
6. Missing side is calculated by considering the tan of 58°
Tan 58°=12/x
x=12/Tan 58°
=7.5
7. Missing side is calculated by considering the sine of 43°
Sin 43°= opposite / hypotenuse
Sin 43 =x/18
x= 18 Sin 43
=12.3
8. Missing side is calculated by considering the sine of 62°
Sin 62° = 13/x
x=13/Sin 62°
=14.7
9. Missing side is calculated by considering the tan of 36°
Tan 36°= 16/x
x=16/Tan 36°
=22.0
10. Missing side is calculated by considering the sine of 23°
Sin 23° = x/16
x=16 Sin 23
=6.3
Answer:
793.25 mi/hr
Step-by-step explanation:
Given that:
The radius of the earth is = 3030 miles
The angular velocity = 
If a jet flies due west with the same angular velocity relative to the ground at the equinox;
We are to determine the How fast in miles per hour would the jet have to travel west at the 40th parallel for this to happen.
NOW;
Distance s is expressed by the relation
s = rθ

s = 793.25
The speed which depicts how fast in miles per hour the jet would have traveled is :


v = 793.25 mi/hr
Hence, the jet would have traveled 793.25 mi/hr due west at the 40th parallel for this to happen.
Answer:
-1/4x
Step-by-step explanation:
11-12/6-2 = -1/4