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OLga [1]
4 years ago
6

How many real number solutions does the equation have?

Mathematics
2 answers:
lisov135 [29]4 years ago
8 0
B is the answer to this
Arturiano [62]4 years ago
4 0
5x^2+2x-12=0 is a quadratic equation. For any ax^2 + bx + c = 0, the solution can be found by completing the square to find the equations 
 x=(-b+sqrt(b^2-4ac))/2a and x=(-b-sqrt(b^2-4ac))/2a  
 Substituting using the equation 0=5x^2+2x-12
 x=(-2+sqrt(2^2-4(5)(-12)))/(2(5)) and x=(-2+sqrt(2^2-4(5)(-12)))/(2(5)) 
 Since the sqrt(244) is a real number, there are two real solutions.
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Step-by-step explanation:

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Aleks04 [339]

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3 years ago
What is the 4th term in the sequence? need help now! (will mark brainlest)
jolli1 [7]
The 4th term is a(4)
by the definition:
a(4) = a(3) * 10
we need a(3)!
a(3) = a(2) * 10
we need a(2)!
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5 0
4 years ago
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Korvikt [17]

Answer:

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4 years ago
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