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Irina-Kira [14]
2 years ago
11

Help thank you Xxxxxxx

Mathematics
2 answers:
enyata [817]2 years ago
5 0
The answer to this is C. I hope this helps you out.
belka [17]2 years ago
5 0
Ok Kenifer Lopez we stan queen why are you doing math?
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A bag holds 13 marbles. 6 are blue, 2 are green, and 5 are red. you select a marble from the bag. what is the probability that t
navik [9.2K]

Answer:

\boxed {\boxed {\sf B. \ \frac{8}{13} }}

Step-by-step explanation:

Probability is found by dividing the number of favorable outcomes by the total number of outcomes.

P= \frac{favorable \ outcomes}{total \ outcomes}

For this problem, the favorable outcome is selecting a blue or green marble. There are 8 outcomes for this because there are 6 outcomes for blue and 2 fr green.

The total outcomes are all the marbles. Each marble could be an outcome, so there are 13 outcomes (1 for each marble).

P(blue \ or \ green) = \frac{8}{13}

This fraction cannot be reduced, so the probability of selecting a blue or green marble is <u>8/13.</u>

7 0
2 years ago
Deshawn has two bags of marbles. The first bag has 2 blue, 3 orange, and 5 red. The second bag has 4 pink, 10 blue, and 6 brown.
madreJ [45]

Answer: 0.1

Step-by-step explanation:

Given

Bag-I has 2 blue,3 orange, 5 red

Bag-II has 4 Pink,10 blue, 6 brown

No of ways of choosing a blue marble from bag-I

\Rightarrow ^2C_1

Total no of ways of choosing a marble from bag-I

\Rightarrow ^{10}C_1

No of ways of choosing a blue marble from bag-II

\Rightarrow ^{10}C_1

Total no of ways of choosing a marble from bag-II

\Rightarrow ^{20}C_1

The probability that he will pull out a blue marble from each bag is

\Rightarrow P=\text{Probability of pulling a blue marble from bag-I}\times \text{Probability of pulling a blue out bag-II}

\Rightarrow P=\dfrac{^2C_1}{^{10}C_1}\times \dfrac{^{10}C_1}{^{20}C_1}\\\\\Rightarrow P=\dfrac{2}{10}\times \dfrac{10}{20}=\dfrac{1}{10}

3 0
3 years ago
Hey all!
Rainbow [258]

Answer:

  • 65°

Step-by-step explanation:

<u>Use the law of cosines:</u>

  • cos C = (25² + 27² - 28²)/(2*25*27)
  • cos C = 0.4222
  • m∠C = arccos 0.4222
  • m∠C = 65°
8 0
2 years ago
M&lt;MRT 133. What is m&lt;MRN?
liberstina [14]

Answer:

MRN+NRT=MRT

2g-2+4g-9=133

6g-11=133

6g=133+11

6g=144

g=144/6

g=24

MRN=2g-2

=2(24)-2

=48-2

=46°

Hope it helps:-)

4 0
3 years ago
Can someone help me with this please
makvit [3.9K]
Rise over run
mx+b
1/3x-1
6 0
2 years ago
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