Ur answer should be 97
Hope this helps u:)
Answer:
Step-by-step explanation:
(2^8 ⋅ 3^−5 ⋅ 6^0)^−2 ⋅ 3
(2^8 ⋅ 3^−5 ⋅ 6^0)^−6
(a^m)^n=a^m*n
So,
(2^8*-6) * (3^−5*-6) * (6^0*-6)
(2^-48) (3^30) (6^0)
a^0=1
So,
(2^-48) (3^30) (1)
<u>(2^-48) (3^30)</u>
I hope this helps you friend!
Answer:
The answer is D
Step-by-step explanation:
Hope this helps UwU