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fenix001 [56]
3 years ago
13

PLEASE HELP ASAP I am kinda stuck on this because my teacher didn’t teach me this

Mathematics
1 answer:
wariber [46]3 years ago
5 0

Answer:

the first option

a = -2

b = 3

Step-by-step explanation:

See photo attached. (:

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Mrs Rivas bought a can of paint he used 3/8 of paint and 1/4 he also used some for a birdhouse and had 1/8 of paint left how muc
Degger [83]

Answer:

The amount of paint used in the  birdhouse = (1/4) of paint

Step-by-step explanation:

The amount of paint used in first go = 3/8

The amount of pain used in second go = 1/4

The amount of paint used in bird house = k

The amount paint left = 1/8

Now, according to the question:

Paint used in ( First go + second go + Birdhouse) + Paint left = 1 can Paint

⇒\frac{3}{8}  + \frac{1}{4} + k + \frac{1}{8}    = 1\\\implies \frac{3 + 1(2) + 1}{8} + k = 1\\ \frac{6}{8} + k = 1 \\\implies k = 1 - \frac{6}{8}  = \frac{8-6}{8}  = \frac{2}{8}  = \frac{1}{4} \\\implies k = \frac{1}{4}

or, The amount of paint used in the  birdhouse = (1/4)

5 0
3 years ago
Correctly order the proceed for solving for x using the algebraic properties of equality.
Snezhnost [94]

Answer:

3

1

2

Step-by-step explanation:

Step 1: Subtract 9

50.24 = 3.14x²

Step 2: Divide by 3.14

x² = 16

Step 3: Square root both sides

x = ±4

6 0
3 years ago
Bryan initially filled a measuring cup with 3/10 of a cup of syrup from a large jug. Then he poured 1/10 of a cup back into the
wariber [46]
2/10. 3-1/10 = 2/10.
7 0
3 years ago
The marked price of an article is Rs 2,800 which is 40 % above the cost price. If it
mixer [17]

Answer:

mp=2800

mp=cp+40%ofcp=cp+40/100×cp=1.4cp

2800=1.4çp

cp=2800/1.4=2000

discount=20%

profit%=?

Step-by-step explanation:

sp=mp-discount%of mp=2800-20/100×2800=2240

profit=sp-cp=2240-2000=240

profit%=profit/cp×100%=240/2000×100%=12%

7 0
3 years ago
Help please!!!!!!!!!!!!
creativ13 [48]

Answer:

\frac{\pi }{3},\:\frac{2\pi }{3}

Step-by-step explanation:

Let a=THETA (angle)

1+\sin \left(a\right)-1=\frac{\sqrt{3}+2}{2}-1\\\sin \left(a\right)=\frac{\sqrt{3}+2}{2}-1\\a=\arcsin \left(\frac{\sqrt{3}+2}{2}-1\right)+2\pi n,\:a=\pi -\arcsin \left(\frac{\sqrt{3}+2}{2}-1\right)+2\pi n\\a=\frac{\pi }{3},\:a=\frac{2\pi }{3}

7 0
3 years ago
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