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3 years ago

150+25x=55x what is the answer?

Mathematics

2 answers:

kirill115 [55]3 years ago

6 0

Answer: x =5

Steps: 150 + 25x = 55x

Subtract 150 from both sides: 150 + 25x - 150 = 55x - 150

Simplify: 25x = 55x - 150

Subtract 55x from both sides: 25x - 55x = 55x - 150 - 55x

Simplify: -30x = -150

Divide both sides by -30: -30x ÷ -30 = -150 ÷ -30

Simplify: x = 5

Plz mark brainliest:)

posledela3 years ago

4 0

Answer:

x = 5

Step-by-step explanation:

150+25x= 55x

-25x -25x

150= 30x

150/30 = 30x/30

x = 5

Hope this helps!

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A bond analyst is analyzing the interest rates for equivalent municipal bonds issued by Georgia and Ohio. A sample of 60 bonds i

slavikrds [6]

Answer:

Since our calculated value is outside than our critical value, $z_{calc}=-136.438$ , we have enough evidence to reject the null hypothesis at 5% of significance. So there is not nough evidence to conclude that mean for Ohio it's significantly different than the mean for Georgia.

Step-by-step explanation:

1) Data given and notation

$\bar X_{1}=3.6$ represent the mean for Georgia

$\bar X_{2}=4.15$ represent the mean for Ohio

$s_{1}=0.03$ represent the population standard deviation for Georgia

$\sigma_{2}=0.01$ represent the population standard deviation for Ohio

$n_{1}=60$ sample size for Georgia

$n_{2}=80$ sample size for Ohio

z would represent the statistic (variable of interest)

$p_v$ represent the p value

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the means are different for both groups, the system of hypothesis would be:

H0: $\mu_{1} = \mu_{2}$

H1: $\mu_{1} \neq \mu_{2}$

If we analyze the size for the samples both are higher than 30, we can assume that the normal distribution is the correct disirbution for the statistic, so for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

3) Calculate the statistic

We have all in order to replace in formula (1) like this:

$z=\frac{3.6-4.15}{\sqrt{\frac{0.03^2}{60}+\frac{0.01^2}{80}}}=-136.438$

4) Find the critical value

In order to find the critical value we need to take in count that we are conducting a two tailed test, so we are looking on the normal standard distribution a value that accumulates 0.025 of the area on the right and 0.975 of the area on the left. We can us excel or a table to find it, for example the code in Excel is:

"=NORM.INV(1-0.025,0,1)", and we got $z_{critical}=\pm 1.96$

5) Statistical decision

Since our calculated value is outside than our critical value, $z_{calc}=-136.438$ , and outside of (-1.96,1.96), we have enough evidence to reject the null hypothesis at 5% of significance. So there is not nough evidence to conclude that mean for Ohio it's significantly different than the mean for Georgia.

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3 years ago

(1 point) A noted psychic was tested for ESP. The psychic was presented with 180 cards face down and was asked to determine if t

Luba_88 [7]

Answer:

a) $z=\frac{0.239 -0.2}{\sqrt{\frac{0.2(1-0.2)}{180}}}=1.308$

b) $p_v =P(z>1.308)=0.0954$

Step-by-step explanation:

Data given and notation

n=180 represent the random sample taken

X=43 represent the correct guesses

$\hat p=\frac{43}{180}=0.239$ estimated proportion correct guesses

$p_o=0.2$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the ture proportion is higher than 0.2 or no.:

Null hypothesis: $p=0.2$

Alternative hypothesis: $p > 0.2$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Part a: Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.239 -0.2}{\sqrt{\frac{0.2(1-0.2)}{180}}}=1.308$

Part b: Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>1.308)=0.0954$

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4 years ago

What is mArc S U? 49° 77° 98° 161°

zvonat [6]

Answer:

77°

Step-by-step explanation:

Find the diagram atached

From the figure

m<T = 1/2(arcRU - arcSU)

m<T = 1/2(119-arcSU)

21 = 1/2(119-arcSU)

21*2 = 119-arcSU

42 = 119-arcSU

arcSU = 119 - 42

arcSU = 77degrees

Hence the meaasure of arcSU is 77degrees

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3 years ago

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