Answer:
4 trays should he prepared, if the owner wants a service level of at least 95%.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 5
Standard Deviation, σ = 1
We are given that the distribution of demand score is a bell shaped distribution that is a normal distribution.
Formula:

P(X > x) = 0.95
We have to find the value of x such that the probability is 0.95
P(X > x)
Calculation the value from standard normal z table, we have,
Hence, 4 trays should he prepared, if the owner wants a service level of at least 95%.
hmmm units rates are just a matter of one above the other.
in this case is points/week.
9/15 points/weeks, we can just divide 9 ÷ 15 = 0.6, or 3/5.
so 0.6 points/weeks.
Answer:
40
Step-by-step explanation:
you add all the numbers up then divide by how many numbers there are
Answer:
SAS
Step-by-step explanation:
Hope this helps :)