First, multiply the 1,500 by 4.3% to come up with $64.50 every three months (the question says compounded quarterly).
$64.50 x 4(quarters in a year) = $258.00 per year
$258.00 x 6 years = $1,548.00
$1,500.00 + $1,548.00 = $3,048.00 balance after six years
Answer:
A sample size of 79 is needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

The margin of error is:
95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.09?
A sample size of n is needed.
n is found when M = 0.09. So






Rounding up to the nearest whole number.
A sample size of 79 is needed.
1200 × 9.95 = 11.940 × 26 =310,440 ÷ 100 = 3,104.40 her commission is $ 3,104.40
Answer:
x= -3 is the answer
UW=3 is the answer..
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A and b I believe I think it is