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Semmy [17]
3 years ago
15

In the below figure what is the value of ∠QPR, in degrees, if ∠SPQ is a straight line? The measure of a straight angle is 180 de

grees.
Mathematics
1 answer:
inysia [295]3 years ago
6 0

Answer:

180

Step-by-step explanation:

spr is one line and qp is another in a perpendicular position

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Find the perimeter of quadrilateral ABCD with vertices A(-2,-2), B(-1,3),
drek231 [11]

Answer:

<h2> 22.2</h2>

Step-by-step explanation:

Step one

given the coordinates

ABCD with vertices A(-2,-2), B(-1,3), C(5, 3), and D(4, -2)

AB=(-2,-2),(-1,3)

BC=(-1,3), (5, 3)

CD=(5, 3),(4, -2)

DA=(4, -2),(-2,-2)

The distance between points AB=

AB= \sqrt (x_2-x_1)^2+(y_2-y_1)^2

AB= \sqrt (-1+2)^2+(3+2)^2\\\\AB= \sqrt 1^2+(5)^2\\\\AB= \sqrt26\\\\AB=5.1

The distance between points BC=

BC= \sqrt (5+1)^2+(3-3)^2\\\\BC= \sqrt 6^2+(0)^2\\\\BC= \sqrt36\\\\BC=6

The distance between points CD

CD= \sqrt (4-5)^2+(-2-3)^2\\\\CD= \sqrt -1^2+(-5)^2\\\\CD= \sqrt26\\\\CD=5.1

The distance between points DA

DA= \sqrt (4+2)^2+(-2+2)^2\\\\DA= \sqrt 6^2+(0)^2\\\\DA= \sqrt36\\\\DA=6

Hence the perimeter = 5.1+6+5.1+6

= 22.2

5 0
2 years ago
The region bounded by y=(3x)^(1/2), y=3x-6, y=0
Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is y = (3x)^{\frac{1}{2} }

⇒ y^{2} = 3x ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

y^{2} - y - 6 = 0

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = \int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx

= \sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}

= [\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} }  }{3}] - [13.5 - 18 - 6 + 12]

= 6 - 1.5

= 4.5 sq. units. (Answer)

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3 years ago
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Answer:

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Step-by-step explanation:

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He has 8 five dollar bills and 2 dollar bills.
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