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djyliett [7]
3 years ago
13

A stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer. If the top laye

r has two​ logs, how many total logs are there in the​ pile?
Mathematics
1 answer:
Svetlanka [38]3 years ago
6 0

Answer:  The total number of logs in the pile is 6.

Step-by-step explanation:  Given that a stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer and the top layer has two​ logs.

We are to find the total number of logs in the pile.

Let n represents the total number of logs in the pile.

Since each subsequent layer has 6 fewer logs then the previous layer, so the number of logs in each layer will become an ARITHMETIC sequence with

first term, a = 32  and  common difference, d = -6.

We know that

the n-th term of an arithmetic sequence with first term a and common difference d is

a_n=a+(n-10)d.

Since there are n logs in the pile, so we get

a+(n-1)d=2\\\\\Rightarrow 32+(n-1)(-6)=2\\\\\Rightarrow 32-6n+6=2\\\\\Rightarrow 6n=36\\\\\Rightarrow n=6.

Thus, the total number of logs in the pile is 6.

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hello

from the question given, the dog walker charges a flat rate of $6 and an extra $30 per hour.

we can write out an equation in function notation

let the number of hours be represented by x

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now we can proceed to solve the cost of the walk for 45 minutes

\begin{gathered} 1hr=60\min s \\ \text{xhr}=45\min s \\ x=\frac{45}{60} \\ x=\frac{3}{4} \\ \text{therefore 45mins = 3/4 hours} \end{gathered}

now we can input the value into the equation and know the cost for 45 minutes walk

\begin{gathered} f(x)=6+30x \\ x=\frac{3}{4} \\ f(x)=6+30(\frac{3}{4}) \\ f(x)=6+22.5 \\ f(x)=28.5 \end{gathered}

from the calculation above, the cost of 45 minutes walk will cost $28.5

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