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3 years ago

5

The given function k is a composition of two functions m and n so that k(x) = (m ∘ n)(x). k (x) = StartFraction 2 Over RootIndex

4 StartRoot 4 x minus 7 EndRoot EndFraction If n(x) = 4x – 7, m(x) must be equal to which expression?

1 answer:

kotykmax [81]3 years ago

6 0

Answer:

$\frac{2}{\sqrt[4]{x} }$

Step-by-step explanation:

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Simplify to a single power of 6:

Anestetic [448]

Answer:

6^2

Step-by-step explanation:

it is a division between two power with the same base, so we have to subtract the exponents

6^(6-4) = 6^2

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3 years ago

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Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu

Luda [366]

Answer:

11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

P(z ≤ -6) ≈ 9.86588×10^-10

and

P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

0.50^t = 0.000290372

t·log(0.50) = log(0.00290372) . . . . take logarithms

t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

t ≈ 11.75

It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

<em>Comment on Six Sigma</em>

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0

3 years ago

Select the graph for the solution of the open sentence. Click until the correct graph appears. |x| > 3/2

Soloha48 [4]

ANSWER

See attachment

EXPLANATION

The given inequality is

$|x| \: > \: \frac{3}{2}$

This implies that,

$x\: > \: \frac{3}{2} \: or \: - x\: > \: \frac{3}{2}$

Multiply both sides of the second inequality by -1 and reverse the inequality sign.

$x\: > \: \frac{3}{2} \: or \: x\: < \: - \frac{3}{2}$

The graphical solution to this inequality is shown in the attachment.

7 0

3 years ago

Help me answer correctly !!!! Will mark Brianliest !!!!!!!!!!!!!!!!

mrs_skeptik [129]

Show the question so I can answer it for you.

6 0

3 years ago

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Given m parallel to n, find the value of x, (7x+14) and (9x-8)

iVinArrow [24]

Answer:

x=11

Step-by-step explanation:

(7x+14)=(9x-8)

7x-9x=-14-8

-2x=-22

-2x/-2=-22/-2

x=11

8 0

2 years ago