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3 years ago

5

The given function k is a composition of two functions m and n so that k(x) = (m ∘ n)(x). k (x) = StartFraction 2 Over RootIndex

4 StartRoot 4 x minus 7 EndRoot EndFraction If n(x) = 4x – 7, m(x) must be equal to which expression?

1 answer:

kotykmax [81]3 years ago

6 0

Answer:

$\frac{2}{\sqrt[4]{x} }$

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago

this is the rust of the questions please please some one helps me because I really try my best to solve it . thank you

lyudmila [28]

Answer:

x = 24.

r $\ne$ 0.

Step-by-step explanation:

2. The given equation is:

$\frac{1}{2} (x - 4) = \frac{1}{3} x + 2$

a) To eliminate the fractions multiply the equation throughout by the LCM of the denominators of the fraction. In this case, the LCM of (2, 3). The LCM is 6. So, multiply the entire equation by 6.

b) Half of the difference between an integer and 4 equals the sum of one - third of the integer and 2. Find the integer.

c) We have the equation:

$\frac{1}{2} (x - 4) = \frac{1}{3} x + 2$

Multiplying throughout by 6, we get:

$\frac{6}{2}(x - 4) = \frac{6}{3} x + 6(2)$

$\implies 3(x - 4) = 2x + 12$

$\implies 3x - 12 = 2x + 12$

$\implies x = 24$

Therefore, the solution of the equation is 24.

3. The given equation is: $ry + s = tx - m$

To solve for y:

We can rearrange the equation as:

$ry = tx - m - s$

$\implies y = \frac{tx - m - s}{r}$

or, $y = \frac{tx - (m + s)}{r}$

Note that we have to impose a condition on variable $r$ . It would be that $r$ can never be zero. i.e., $r \ne 0$ . Otherwise, the value of $y$ would be undefined.

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3 years ago

Consider the equation LaTeX: pN=kVT p N = k V T , where k is a constant. Select all of the correct answers that describe the var

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Answer: did u ever get the right answer?

Step-by-step explanation:

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3 years ago

Which expression is equivalent to 7a^3(6a^2+a^2)-4a^6?

Thepotemich [5.8K]

Simply simplify:

7a³(7a²)-4a^6 ⇒ 49a^6 - 4a^6 ⇒ 45a^6

Hope that helps!

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3 years ago

Geometry Question Help if you can please

docker41 [41]

Answer:

≈ 78.55 cm

Step-by-step explanation:

Using the ratio of arc (AB) to circumference (C) is equal to the ratio of angle subtended at centre by arc AB to 360°, that is

$\frac{AB}{C}$ = $\frac{110}{360}$ , that is

$\frac{24}{C}$ = $\frac{110}{360}$ ( cross- multiply )

110C = 8640 ( divide both sides by 110 )

C = $\frac{8640}{110}$ ≈ 78.55 cm ( to 2 dec. places )

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3 years ago