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vivado [14]
3 years ago
15

Rectangle x measures 7cm by (x+1)cm. Rectangle B has dimensions of (3x+6)cm and 4cm. The area of rectangle X is half the area of

rectangle Y. Calculate the lengths of the sides of the rectangles, and hence, their areas.
Mathematics
1 answer:
kirill115 [55]3 years ago
6 0
Lengthxwidth=area and rectangle Y/B is twice as big as X so 

7(x+1)=1/2(4)(3x+6)
7x+7=1/2(12x+24)
x=5

Rectangle X=7(5+1)=42
Rectangle Y=4(3*5+6)=84

84 is twice as big as 42 :D
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