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IceJOKER [234]
3 years ago
13

If George is 33 1/3% richer than Pete, than Pete is what percent poorer than George?

Mathematics
1 answer:
OleMash [197]3 years ago
3 0

Answer:

25%

Step-by-step explanation:

George is 33\frac{1}{3}% (\frac{100}{3}%) richer than Pete. Let Pete's percentage of wealth be 100%.

Thus George percentage of wealth = 100% + \frac{100}{3}%

                                                           = \frac{400}{3}%

                                                           = 133\frac{1}{3}%

Pete's percent poorer than George can be determined by;

                                                           = (\frac{100}{3}) ÷ (\frac{400}{3} ) × 100

                                                           = (\frac{100}{3}) × \frac{3}{400} ×100

                                                           = 0.25 × 100

                                                           = 25%

Pete is 25% poorer than George.

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