1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marrrta [24]
3 years ago
10

What else would need to be congruent to show that ABC XYZ by ASA?

Mathematics
2 answers:
Naddik [55]3 years ago
8 0

Answer: The correct option is (D) AC ≅ XZ.

Step-by-step explanation: Given that in ΔABC and ΔXYZ, ∠X ≅ ∠A and ∠Z ≅ ∠C.

We are to select the correct condition that we will need to show that the triangles ABC and XYZ are congruent to each other by ASA rule..

<u>ASA Congruence Theorem: </u> Two triangles are said to be congruent if two angles and the side lying between them of one triangle are congruent to the corresponding two angles and the side between them of the second triangle.

In ΔABC, side between ∠A and ∠C is AC,

in ΔXYZ, side between ∠X and ∠Z is XZ.

Therefore, for the triangles to be congruent by ASA rule, we must have AC ≅ XZ.

Thus, (D) is the correct option.

docker41 [41]3 years ago
5 0
Side XZ needs to be congruent to side AC. The answer is D.
You might be interested in
Which decimal and percent represents 7/8
Butoxors [25]

Answer:

decimal - 0.875

percent - 87.50%

Step-by-step explanation:

3 0
3 years ago
What does the graph of the following equation look like?
patriot [66]
It is line/linear because for it to be a parabola the x would have to be squared.
5 0
3 years ago
Read 2 more answers
URGENT PLEASE HELP!!!!!
telo118 [61]

(1)

we are given

\frac{y}{6} =x

we can  find for y

multiply both sides by 6

\frac{y}{6}*6 =6*x

y=6x

we can see that y is directly proportional to x

so, option-D........Answer

(2)

y varies inversely with x

so, we can write it as

y=k\frac{1}{x}

now, we are given

y=5 when x=2.5

so, we can plug it here

5=k\frac{1}{2.5}

and then we can solve for k

5*2.5=2.5*k\frac{1}{2.5}

k=12.5

now, we can plug back

y=\frac{12.5}{x}

we can plug x=20

y=\frac{12.5}{20}

y=0.625.............Answer

(3)

we are given

The current, I, in a circuit varies inversely with the resistance, R

so, we can write it as

I=\frac{k}{R}

we have R=12 when I=3

so, we can plug it

3=\frac{k}{12}

now, we can solve for k

3*12=12*\frac{k}{12}

k=36

now, we can plug back

I=\frac{36}{R}

we can plug R=6

I=\frac{36}{6}

I=6................Answer


6 0
3 years ago
PLSS HELP NO BOTS!!!!
ad-work [718]

Answer:

60 degrees

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The table represents a linear equation. Which equation correctly uses point (–2, –6) to write the equation of this line in point
sineoko [7]

Answer:

y+6=m(x+2)

where I would have to look at the table to know m.

Step-by-step explanation:

Point-slope form of a line is

y-y_1=m(x-x_1)

where m \text{ is the slope and } (x_1,y_1) \text{ is a point on that line}

You are given (x_1,y_1)=(-2,-6) \text{, but no value for }m.

So we know we are looking for an equation that looks like this:

y-(-6)=m(x-(-2))

If you simplify this looks like:

y+6=m(x+2)

6 0
3 years ago
Read 2 more answers
Other questions:
  • Help needed plssssssssss :)))
    5·1 answer
  • What is the answer???
    7·2 answers
  • I need the answer Pleaseee
    14·1 answer
  • If $4,000,000 is invested at 5% interest compounded continuously, how much
    8·1 answer
  • Which of the following are true statements?
    12·2 answers
  • Drinking 6 fluid ounces of milk provides 202.5 milligrams of calcium. how many fluid ounces of milk provide 85.5 milligrams of c
    12·2 answers
  • PLEASE HELP THANK YOU:
    12·2 answers
  • Pls help me with this. will make u brainliest
    9·1 answer
  • A local boys club sold 136 bags of mulch and made a total of $521. It sold two types of mulch: hardwood for $4.00 a bag and pine
    8·1 answer
  • Help me this is difficult ​
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!