Question

Using the transformation T: (x, y) (x + 2, y + 1), find the distance named. Find the distance BB'

Answer 1

Answer:

$\sqrt{5}\ units$

Step-by-step explanation:

we know that

The rule of the translation is equal to

$(x,y)-----> (x+2,y+1)$

That means

The translations is $2$ units to the right and $1$ unit up

Let

$(x,y)$-------> the coordinates of point B

$(x+2,y+1)$------> the coordinates of point B'

Find the distance

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

substitute

$d=\sqrt{((y+1)-y)^{2}+((x+2)-x)^{2}}$

$d=\sqrt{(1)^{2}+(2)^{2}}$

$d=\sqrt{5}\ units$

Answer 2

The transformation is:
T : ( x , y ) → ( x + 2, y + 1 )
B ( 1, 3 ) → B` ( 1 + 2, 3 + 1 )
B ` ( 3, 4 )
d ( B B`) = √(( 3 - 1 )² + ( 4 - 3 )² )=
=  √ (2² + 1²) = √ 5