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Nat2105 [25]
3 years ago
9

Using the transformation T: (x, y) (x + 2, y + 1), find the distance named. Find the distance BB'

Mathematics
2 answers:
AnnZ [28]3 years ago
8 0

Answer:

\sqrt{5}\ units


Step-by-step explanation:

we know that

The rule of the translation is equal to

(x,y)-----> (x+2,y+1)

That means

The translations is 2 units to the right and 1 unit up

Let

(x,y)-------> the coordinates of point B

(x+2,y+1)------> the coordinates of point B'

Find the distance

the formula to calculate the distance between two points is equal to


d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}


substitute

d=\sqrt{((y+1)-y)^{2}+((x+2)-x)^{2}}


d=\sqrt{(1)^{2}+(2)^{2}}


d=\sqrt{5}\ units


Nonamiya [84]3 years ago
5 0
The transformation is:
T : ( x , y ) → ( x + 2, y + 1 )
B ( 1, 3 ) → B` ( 1 + 2, 3 + 1 )
B ` ( 3, 4 )
d ( B B`) = √(( 3 - 1 )² + ( 4 - 3 )² )=
=  √ (2² + 1²) = √ 5
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(a^4 - 6a^2b^2+ b^4) - (-2a^4+5a^2b^2+ 3b^4)

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Open brackets

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