The value of x and y is 5 , 7
<h3>What is an Equation ?</h3>
An expression consists of variables , constants and mathematical operators , when equated by any other algebraic expression or a constant it becomes an equation.
The equation given in the question is
(x + 1)/2 -(y+4)/11 = 2
(x+3) /2 + (2y+3)/17 = 5
It has to be solved for x and y ,
The simplification of the equation has to be done
and the equation is
11x-2y = 41 -----------1
and
17x +4y = 113 -------------------2
to find the solution elimination method will be followed as
Multiplying equation 1 by 2 and adding the both equations
39x = 195
x = 5
Substituting this value in equation 1
55 -2y = 41
y = 7
The value of x and y is 5 , 7
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I^63
=i*(i^(2*31))
=i*(i^2)^31
i^2=-1
=(-1)^31*i
=-1*i
=-i
<u>(x-5)²+(y-5)²=36</u>
Answer:
Solution given:
radius [r]=6 units
centre[h,k]=(5,4)
we have
the equation of a circle is;
(x-h)²+(y-k)²=r²
(x-5)²+(y-5)²=6²
<u>(</u><u>x-5</u><u>)</u><u>²</u><u>+</u><u>(</u><u>y-5</u><u>)</u><u>²</u><u>=</u><u>3</u><u>6</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>equation</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>circle</u><u>.</u>
Hi there. :)
I'll try to make this simpler for you.
Let's focus on the equation from left to right, to avoid clutter.
-4(3 * 1/2) = -4(1.5)
Now to the right.
+ 2(3) = + 6
Now combine!
-4(1.5) + 6 =
-6 + 6 = 0
The answer is 0.
