Question

Please help me :

Answer 1

(x-5)²+(y-5)²=36

Answer:

Solution given:

radius [r]=6 units

centre[h,k]=(5,4)

we have

the equation of a circle is;

(x-h)²+(y-k)²=r²

(x-5)²+(y-5)²=6²

(x-5)²+(y-5)²=36 is a required equation of a circle.

Answer 2

Answer:

(x - 5)^2 + (y - 4)^2 = 6^2

Step-by-step explanation:

The standard equation of a circle of center (h, k) and radius r is:

(x - h)^2 + (y - k)^2 = r^2.

Here we are given the center (5, 4) and the radius r =  6.

Substituting these values into the standard equation, we get:

(x - 5)^2 + (y - 4)^2 = 6^2