Answer:
Here, F = 2.911
F > 2.739502 , so reject null hypothesis ( H0)
There is ample evidence to indicate a disparity in the means for the different forms of mails.
Step-by-step explanation:
Null hypothesis - H₀: μ₁ = μ₂ = μ₃ = μ₄
Alternative hypothesis - H₁: At least one mean is different.
df1 is factor degree of freedom and df2 is error degree of freedom.
Decision rule - Reject H₀ if F > F₀.₀₅, (df1, df2)
F0.05, df1,df2 is f critical value at \alpha = 0.05
Here df1 = 3 , and df2 = 68
Using Excel,
F₀.₀₅, ₃, ₆₈ = FINV( 0.05, 3 , 68 ) = 2.739502302
So reject H0 if F > 2.739502
Here, F = 2.911
F > 2.739502 , so reject null hypothesis ( H0)
There is ample evidence to indicate a disparity in the means for the different forms of mails.
