Let's solve your system by substitution.
−3x+y=−2;y=4x
Rewrite equations:
y=4x;−3x+y=−2
Step: Solvey=4xfor y:
y=4x
Step: Substitute4xforyin−3x+y=−2:
−3x+y=−2
−3x+4x=−2
x=−2(Simplify both sides of the equation)
Step: Substitute−2forxiny=4x:
y=4x
y=(4)(−2)
y=−8(Simplify both sides of the equation)
Answer:
x=−2 and y=−8
(2,3) so x=2, y=3 and h=(2^2+3^2)^(1/2)=√13
sina=3/√13, cosa=2/√13, tana=3/2
Afterwards multiply sina and cosa by √13/√13 and get sina=(3√13)/13 and cosa=(2√13)/13
Answer:2
Step-by-step explanation: