3 years ago

Which is the equation of a line that has a slope of and passes through point (–3, –1)?

Mathematics

1 answer:

Leno4ka [110]3 years ago

3 0

There's no slope, so it's impossible to answer your question. I'm sorry.

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Find the solution of the given initial value problem. ty' + 6y = t2 − t + 1, y(1) = 1 6 , t > 0

gtnhenbr [62]

Answer:

Step-by-step explanation:

Given is a differential equation as

$ty' + 6y = t^2 - t + 1, y(1) = 1 6 , t > 0$

Divide this by t to get in linear form

$y'+6y/t = t-1+1/t$

This is of the form

y' +p(t) y = Q(t)

where p(t) = 1/t $e^(\int 1/tdt) = t$

So solution would be

$yt = \int t^2-t+1 dt\\= t^3/3-t^2/2+t+C$

siubstitute y(1) = 16

$16 = 16^3/3-128+1+C\\C = -1206$

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3 years ago

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xeze [42]

Answer:

JM = 10

Step-by-step explanation:

Because MN║JL,

$\frac{MK}{JM} = \frac{KN}{NL}$

$\frac{5}{2x + 4} = \frac{6}{12}$ = $\frac{1}{2}$

2(5) = 1(2x + 4)

10 = 2x + 4

2x = 6

x = 3

JM = 2x + 4 = 2(3) + 4 = 6 + 4 = 10

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solong [7]

Answer:

the answer for this question is c

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umka2103 [35]

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Which is a factor of x2 – 9x + 14?<br> x – 9<br> x – 2<br> x + 5<br> x + 7

bija089 [108]

$x^2-9x + 14 = \boxed{\bf{(x-2)(x-7)}}$

Your answer is x - 2.

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3 years ago

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