Answer:
The function f(x) = -9.5 + 6 + x² is neither odd or even.
Step-by-step explanation:
We know that a function is termed as 'even' when
f(-x) = f(x) for all x
We know that a function is termed as 'odd' when
f(-x) = -f(x) for all x
Given the function
f(x) = -9.5x⁵ + 6 + x²
substitute x with -x
f(-x) = -9.5(-x)⁵ + 6 + (-x)²
as (-x)⁵ = -x⁵, so
f(-x) = -(-9.5x)⁵ + 6 + (-x)²
Apply exponent rule: (-a)ⁿ = aⁿ, if n is even
f(-x) = -(-9.5x)⁵ + 6 + x²
Apply rule: -(-a) = a
f(-x) = 9x⁵ + 6 + x²
As
f(-x) ≠ f(x) ≠ -f(x)
Therefore, the function f(x) = -9.5 + 6 + x² is neither odd or even.
Let us assume the unknown number = x
Now we have to follow the details given in the question to bring out the actual equation. In this case there will be only one equation.
(x/3)^2 - (2x + 7) = 0
(x/3)^2 = 2x + 7
x^2/9 = 2x + 7
x^2 = 9(2x + 7)
x^2 = 18x + 63
x^2 - 18x = 63
This would be the final equation for the given problem. his problem needs any solver to understand the words very minutely.
Answer:
Step-by-step explanation:
take 23 degree as reference angle
using tan rule
tan 23=opposite/adjacent
0.42=25/x
x=25/0.42
x=59.52
x=60
Answer: the expression that is equivalent to that is 42
