Speed is distance traveled per block of time. As an equation, this is
Speed = distance/time
In your problem, the given distance is 300km, and the time is 2.5 hours.
Plugging into the equation,
Speed = 300km / 2.5 h
Speed = 120 km/h
Velocity is speed <em>and</em> direction.
The velocity would be 120 km/h north.
Answer:
1. -7
2. 212
3. -49
4.-1,991
5. 78
6. -16
7. 2
8. 100
9. 16
10. 16
11. 13
12. 75
13. |12| = 12
14.|12| = 12
15. |8|
16.| 10|
17.15
18. 1,400
Step-by-step explanation:
Step One
======
Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
Answer:
translation,reflection,
Step-by-step explanation:
because you move thing in different direction
Answer
at first I said 1/2 but it's 2/5's.
Step-by-step explanation:
