"Let A = the number of model A grates and let B = the number of model B clock grates. In this application, write the constraint
for the number of pounds of iron: Kane Manufacturing has a division that produces two models of grates, model A and model B. To produce each model A grate requires 3 lb of cast iron and 6 min of labor. To produce each model B grate requires 4 lb of cast iron and 3 min of labor. The profit for each model A grate is $2, and the profit for each model B grate is $1.50. Available for grate production each day are 100 lb of cast iron and 20 hr of labor. Because of a backlog of orders for model B grates, Kane’s manager has decided to produce at least 180 model B grates per day. How many grates of each model should Kane produce to maximize its profits?"
In this problem, if we solve it by linear programming one of the conditions does not satisfy which is - number of B should be produced at least 180 in order to meet backlog. This means for B only we need 180* 4 = 540 lbs of iron where as daily supply is only of 100 lbs.
for this option (3) looks viable i.e. 3A + 4B <= 100
Step; This conversion of 10.03 kilometres to hectometres has been calculated by multiplying 10.03 kilometres by 10 and the result is 100.3 hectometres.-by-step explanation:
