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3 years ago

1. The model represents an equation.

Mathematics

1 answer:

muminat3 years ago

8 0

Answer:

yes correc I relly tink

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Can someone help me pls

Gnesinka [82]

Point M bisects Line RS. The length of RS is also 44 because RM and MS are congruent and MS has a length of 22.

4 0

3 years ago

Omar rented a truck for one day. There was a base fee of $17.95, and there was an additional charge of 98 cents for each mile dr

stiv31 [10]

The given question is incomplete. The complete question is:

Omar rented a truck for one day. There was a base fee of $17.95, and there was an additional charge of 98 cents for each mile driven. Omar had to pay $23 when he returned the truck. For how many mile did he drive the truck?

Answer: Omar drove the truck for 5.15 miles

Step-by-step explanation:

Base fee = 17.95 $

Additional charge per mile = 98 cents = 0.98 $ ( 100cents = 1$)

Now Omar payed = 22 $

Let the miles he travelled = x

Now , $17.95+0.98\times x=23$

Solvimg for x :

$x=5.15miles$

Thus Omar drove the truck for 5.15 miles

5 0

3 years ago

What is the greatest common factor of 48 and 84? A.8 B.12 C.4 D.24

LiRa [457]

48 = 2*2*2*2*3
84 = 2*2*3*7

Looking for common factors we get the GCF to be 2*2*3 = 12

Its B

7 0

4 years ago

Which expression is equal to 54⋅58 ? <br> 512 54 52 5−4

nignag [31]

Not sure if it's one of the answer you listed.
The • means multiplication, so it would be
54 times 58, which equals 3,132.

7 0

4 years ago

Read 2 more answers

Cual es la respuesta de (x10+10y12) al cuadrado

padilas [110]

Answer:

$\mathrm{Expand}\:\left(x^{10}+10y^{12}\right)^2:\quad x^{20}+20x^{10}y^{12}+100y^{24}$

Step-by-step explanation:

$\left(x^{10}+10y^{12}\right)^2$

$\gray{\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2}$

$\gray{a=x^{10},\:\:b=10y^{12}}$

$=\left(x^{10}\right)^2+2x^{10}\cdot \:10y^{12}+\left(10y^{12}\right)^2$

$\black{\mathrm{Simplify}\:\left(x^{10}\right)^2+2x^{10}\cdot \:10y^{12}+\left(10y^{12}\right)^2:}$

$\left(x^{10}\right)^2+2x^{10}\cdot \:10y^{12}+\left(10y^{12}\right)^2$

$\gray{\left(x^{10}\right)^2=x^{20}}$

$\gray{2x^{10}\cdot \:10y^{12}=20x^{10}y^{12}}$

$\gray{\left(10y^{12}\right)^2=100y^{24}}$

$=x^{20}+20x^{10}y^{12}+100y^{24}$

6 0

3 years ago