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4 years ago

If the second term of an arithmic progression is -3 and the fourth term is 5, find the ninth term

Mathematics

1 answer:

Novosadov [1.4K]4 years ago

8 0

Answer:

Step-by-step explanation:

You can get that the common difference for all of the terms if four by finding the difference between -3 and 5, which gives us four. Using this, we can calculate the last term by doing 5+4*5 which is 25.

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2^x-1 +2 ^ 2+ 2 ^ x =3 ^ 2 : 1/ 2^ 5

Nina [5.8K]

2−1+22+2=32125

Step-by-step explanation:

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4 0

3 years ago

34 points to whoever can answer this question !! :D

masha68 [24]

- 2 3/5 - 1 2/3

= -2 9/15 - 1 10/15

= (-2 9/15) + (- 1 10/15)

= -3 19/15

= -4 4/15

Answer is B

-4 4/15

8 0

3 years ago

Read 2 more answers

What the constant proportionality of y=26x

UNO [17]

Answer:

Here is a link to help you. This is a very great video that will help you understand proportionalities .

Step-by-step explanation:

https://www.khanacademy.org/math/cc-seventh-grade-math/cc-7th-ratio-proportion/7th-constant-of-proportionality/v/constant-of-proportionality-from-equation

5 0

3 years ago

A 5'6" person walking down the street notices his shadow. If the angle of elevation from the tip of the shadow to the sun is 60°

S_A_V [24]

Check the picture below.

7 0

4 years ago

Find all points on the circle (x^2) + (y^2) = 676 where the slope is 5/12

borishaifa [10]

Implicit defferentation

remember that dy/dx y= dy/dx

so
take derivitive of both sides
$2x+2y \space\ \frac{dy}{dx}=0$
solve for $\frac{dy}{dx}$
minus 2x both sides
$2y \space\ \frac{dy}{dx}=-2x$
divide both sides by 2y
$\frac{dy}{dx}=\frac{-2x}{2y}$
$\frac{dy}{dx}=\frac{-x}{y}$

when is the slope equal to $\frac{5}{12}$
solve for $\frac{dy}{dx}=\frac{5}{12}$
$\frac{dy}{dx}=\frac{5}{12}$
$\frac{5}{12}=\frac{-x}{y}$
$5y=-12x$
$y=\frac{-12}{5}x$
find where the circle and this line intersects

substitute $\frac{-12}{5}x$ for y
$x^2+(\frac{-12}{5}x)^2=676$
$x^2+\frac{144}{25}x^2=676$
$\frac{25}{25}x^2+\frac{144}{25}x^2=676$
$\frac{169}{25}x^2=676$
times both sides by $\frac{25}{169}$
$x^2=100$
sqrt both sides, take positive and negative roots
x=+/-10

sub back

$y=\frac{-12}{5}x$
$y=(\frac{-12}{5})(10) \space\ or \space\ (\frac{-12}{5})(-10)$
$y=\frac{-120}{5} \space\ or \space\ \frac{120}{5}$
$y=-24 \space\ or \space\ 24$

the points are (10,-24) and (-10,24)

8 0

3 years ago