3 years ago

Write an equation in slope intercept form for the line perpendicular to y=8x-9 that passes through the point (9, -8)

Mathematics

1 answer:

svet-max [94.6K]3 years ago

8 0

$y = (1 \div 8)x - 6.87$

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Mazyrski [523]

Answer:

39- 28= 11

Step-by-step explanation:

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4 years ago

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Factor completely 3x^2+9x-3<br>3(x^2+3)<br>3(x^2+3-1)<br>3x(x^2+3x-1)<br>prime

Firdavs [7]

Answer:

Answer from the answer data to choose from

Factor completely

$3\left(x+\dfrac{3-\sqrt{13}}{2}\right)\left(x+\dfrac{3+\sqrt{13}}{2}\right)$

Step-by-step explanation:

$3x^2+9x-3=(3)(x^2)+(3)(3x)-(3)(1)\\\\=(3)(x^2+3x-1)\\\\\text{For}\ x^2+3x-1\ \text{use the quadratic formula}\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x^2+3x-1\to a=1,\ b=3,\ c=-1\\\\x=\dfrac{-3\pm\sqrt{3^2-4(1)(-1)}}{2(1)}=\dfrac{-3\pm\sqrt{9+4}}{2}=\dfrac{-3\pm\sqrt{13}}{2}=-\dfrac{3\pm\sqrt{13}}{2}\\\\3x^2+9x-3=3\left(x+\dfrac{3-\sqrt{13}}{2}\right)\left(x+\dfrac{3+\sqrt{13}}{2}\right)$