Question

What is the area of this figure? Enter your answer in the box. ___ in²

Answer 1

16 * 20 + .5 * 20 * 8 = 320 + 80 = 400

Answer 2

ANSWER

$400 \: {in}^{2}$

EXPLANATION

The figure is made up of a parallelogram and a right angle triangle.



The area of the parallelogram is

$= base \times height$


The base of the parallelogram is 20 inches.




The height of the parallelogram is 16 inches.


The area of the parallelogram is

$= 20 \times 16 \: i {n}^{2}$


$=320 \: i {n}^{2}$





The area of the triangle is

$= \frac{1}{2} \times base \times height$

The base of the parallelogram is also 20 inches because opposite sides of a parallelogram are equal in length.




This implies that the area of the triangle is

$= \frac{1}{2} \times 20 \times 8 \: {in}^{2}$



$= 10 \times 8 \: {in}^{2}$



$= 80 {in}^{2}$



We add the two areas to get the area of the figure.


$= 320 + 80 \: {in}^{2}$



$= 400 \: {in}^{2}$