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omeli [17]
3 years ago
9

Given:

Mathematics
2 answers:
Blababa [14]3 years ago
8 0

The symmetric property and perpendicular property

ICE Princess25 [194]3 years ago
5 0

Answer:

the only following lines which support the conclusion based on the given information is, RZ = RZ , Reflexive Property

Explanation:

HL (Hypotenuse Leg) theorem states that if the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle, then the triangles are congruent.

In ΔRZS and ΔRZT

\angle 3 = \angle 4 = 90^{\circ}   [Given]

RS = RT             [Hypotenuse side]        [Given]

RZ = RZ            [Reflexive property]      

Then, by the HL theorem;

\triangle RZS \cong \triangle RZT               Hence proved!

 

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I need help! Anyone…I don’t understand it.
ziro4ka [17]

Answer:

Step-by-step explanation:

okay is there a graph for it? or is it just like that?

5 0
3 years ago
-2x - y = -9<br><br>5x -2y = 18<br>Solve as a whole number
nexus9112 [7]

Answer:

x = 4, y = 1

(4, 1)

Step-by-step explanation:

-2x - y = -9

5x -2y = 18

-2x - y = -9

+2x     +2x

-y = 2x - 9

/-1    /-1

y = -2x + 9

5x -2y = 18

5x - 2(-2x + 9) = 18

5x + 4x - 18 = 18

9x - 18 = 18

    + 18   + 18

9x = 36

/9  /9

x = 4

Now, we solve for y:

-2(4) - y = -9

-8 - y = -9

+ 8     +8

-y = -1

/-1  /-1

y = 1

(x, y) -> (4, 1)

Hope this helps!

6 0
3 years ago
What is the solution of the equation x+6=7
ruslelena [56]

Answer:

1

Step-by-step explanation:

7 - 6 = 1

1 = x

8 0
3 years ago
Find the slope of the line that goes through (-4,5) and (3,-1)
scZoUnD [109]
Slope = (-1 - 5)/(3 + 4) = -6/7

answer
-6/7
4 0
4 years ago
Read 2 more answers
b is the midpoint of AC and E is the midpoint of BD if A(-9,-4) C(-1,6) and E(-4,-3) find the coirdinates of D
natima [27]

To find the coordinate of the point D, we can use the Midpoint point of a line Segment formula. Calculation of the formula are as follows,

Given two points A(x1,y1) and C(x2,y2), we need to locate the midpoint coordinate of this line denoted as B(x,y).

To solve for the value of x and y, we get,

x=(x1+x2)/2 and y=(y1+y2)/2

For the given problem, we need to solve first the midpoint coordinate of AC which is B.

So, A(-9,-4)=A(x1,y1) and C(-1,6)=C(x2,y2)

Hence,

B(x,y)=B((-9+(-1))/2, (-4+6)/2)=B(-10/2,2/2)=B(-5,1)

Now, since the midpoint is given but one point in the line is missing. To solve for the missing point D(x2,y2), we need to use the Midpoint Segment Formula.

 That is, B(-5,1)=B(x,y) and E(-4,-3)=E(x1,y1)

So,

x=(x1+x2)/2 and y=(y1+y2)/2

-5=(-4+x2)/2 and 1=(-3+y2)/2

By Cross Multiplication and Transposing method,

-5(2)=-4+x2 and 1(2)=-3+y2

x2=-10+4=-6 and y2=3+2=5

Thus, the coordinate of D is D(-6,5).

5 0
4 years ago
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