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Galina-37 [17]
3 years ago
6

I need help! Anyone…I don’t understand it.

Mathematics
1 answer:
ziro4ka [17]3 years ago
5 0

Answer:

Step-by-step explanation:

okay is there a graph for it? or is it just like that?

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Vanessa deposits $24,000 into each of two savings accounts. Account I earns 2. 4% interest compounded annually. Account II earns
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The sum of the balances of these accounts at the end of 5 years is given by: Option B: $53,901.59 (approx)

<h3>How to calculate compound interest's amount?</h3>

If the initial amount (also called as principal amount) is P, and the interest rate is R% per unit time, and it is left for T unit of time for that compound interest, then the interest amount earned is given by:

CI = P(1 +\dfrac{R}{100})^T - P

The final amount becomes:

A = CI + P\\A = P(1 +\dfrac{R}{100})^T

<h3>How to calculate simple interest amount?</h3>

If the initial amount (also called as principal amount) is P, and the interest rate is R% annually, and it is left for T years for that simple interest, then the interest amount earned is given by:

I = \dfrac{P \times R \times T}{100}

For the considered case, we're given that:

  • Initial amount in both accounts deposited = $24,000 = P
  • Type of interest: Compound interest in first account and simple interest in second account
  • Unit of time: Annually
  • Rate of interest = 2.4% annually = R
  • Total unit of time for which amount is to be calculated: 5 years = T

In first account, the final amount at the end of 5 years is evaluated as:

A = 24000(1 + \dfrac{2.4}{100})^4 = 24000(1.024)^4  \approx 27021.59\: \rm (in \:  dollars)

In second account,  the final amount at the end of 5 years is evaluated as:

A = 24000 +  \dfrac{24000 \times 2.4 \times 5}{100} = 24000 + 2880 = 26880 \text{\: (in dollars)}

Total amount after 5 years in these accounts = 27021.59 + 26880 = 53901.59 (in dollars)

Thus, the sum of the balances of these accounts at the end of 5 years is given by: Option B: $53,901.59 (approx)

Learn more about compound interest here:

brainly.com/question/11897800

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