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amid [387]
4 years ago
8

Calculate and reduce to simplest form the fraction 6 1/7 + 11/21

Mathematics
2 answers:
bazaltina [42]4 years ago
8 0

6 \frac{1}{7}  =  \frac{6 \times 7 + 1}{7}  =  \frac{42 + 1}{7}  =  \frac{43}{7}  \\  \\ 6 \frac{1}{7} +  \frac{11}{21}  = \frac{43}{7} + \frac{11}{21}  \\  \\  lcm \: of \: denominators(7 \: and \: 21) = 21 \\  \\   = \frac{43 \times 3 + 11 \times 1}{21}  \\  \\  =  \frac{129 + 11}{21}  \\  \\  =  \frac{140}{21}  =  \frac{7 \times 20}{7 \times 3}  =  \frac{20}{3}   \\  \\ = \boxed{  \red{6 \frac{2}{3} }}
Sergio [31]4 years ago
6 0

The correct answer is 6 2/3.

In order to find this we first need to give the fractions the same denominator.

6 1/7 = 6 3/21

Now that we have this, we can add the fractions together.

6 3/21 + 11/21 = 6 14/21

And to reduce, you'll notice both parts of the fraction are divisible by 7.. So we divide by a factor of 7.

6 2/3

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Jeanne babysits for $6 per hour. She also works as a reading tutor for $10 per hour. She is only allowed to work 20 hours per we
Maru [420]
A) System of inequalities

Income from babysitting: 6x
Income from tutoring: 10y

Goal for this week: at least $ 75 => 6x + 10y ≥ 75
Number of hours: maximum $20 => x + y ≤ 20

x and y have to be zero or positvie => x≥0 and y ≥ 0

Answer of part A.

6x + 10y ≥ 75
x+y ≤ 20
x ≥ 0
y ≥ 0

Part B. Graph

The solution is a region closed by 4 lines and you can find it in the file attached.

In that graph:

1) the line x + y = 20 is the upper limit
2) the line 6x + 10 y = 75 is the lower incclined line
3) y = 0 is the botton horizontal line it is the x-axis
4) x = 0 is the left vertical line, in is the y-axis

Part C.

Use, for example the point (7,10).

It is in the region of the graph limited by the above equations.

It implies:

Number of hours worked = 7 + 10 = 17 which is less than 20.

Income: 6(7) + 10(10) = 42 + 100 = 142, which is greater than 75

Of course, both are greater than 0.

In this way we proved that the point (7,10) is a true solution for the model.






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8 0
3 years ago
The set of all even whole numbers greater than 6 and less than 16 can be written as:
Arlecino [84]
Set L because the answer has to be all even numbers bigger then 6 so 6 can't be added in and smaller then 16 so it can't have 16 in it ether so that leaves 8 10 12 14
4 0
3 years ago
Read 2 more answers
In the coordinate plane, quadrilateral ABCD has vertices A(-2, 3), B(4,5), C(10, -1), and D(8, -9). Let E, F, G, and H
Aliun [14]

Answer:

 G(3, 1), H(2, 3)

Step-by-step explanation:

When D is the midpoint of EG, it means ...

 D = (E + G)/2

or

 G = 2D -E = 2(3,4) -(3,7) = (2·3-3, 2·4-7) = (3, 1)

Likewise, H is ...

 H = 2D -F = 2(3,4) -(4,5) = (2·3-4, 2·4-5) = (2, 3)

not my answer but i hope it helps you.

4 0
3 years ago
Animals at a dog shelter a 24 pound bag of dog food will feed 36 dogs a day. how many dogs would you expect to feed with a 16- p
Ierofanga [76]

Answer: 24 dogs

Step-by-step explanation:

24 lb                     16 lb

--------         =      -------------

36 dogs                x dogs

24x = 576

x = 24

4 0
3 years ago
How would you explain to a friend , the process for finding the total surface area of a cylinder using the net of a cylinder?
Artemon [7]

The toal surface area of a cylinder is 2πrh+2πr²

Step-by-step explanation:

The "net" of any geometrical shape refers to the two-dimensional equivalents of the three-dimensional object.  

e.g. geometrical net of a cylinder would consist of two circles (one each at top and bottom) and a rectangle extending from bottom to the top in a curvilinear manner.

Hence, the Total surface area (TSA) of the cylinder can be found

by considering cylinder to be made of three parts

  • the circle at the bottom
  • the circular tube which extends for height "h" of the cylinder
  • the circle at the top (considering it is closed cylinder)

The surface area of a circle (for 2-dimensional figures surface area is the same as area since the thickness factor is 1)= πr²

Since there are two circles= surface area (combined)= 2πr²

Moreover, this circle extends to height h. Hence, the combined surface area of the circle extending to height h (int he forms of the tube)= circumference*height= 2πrh

hence TSA= 2πrh+ 2πr²

5 0
3 years ago
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