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alina1380 [7]
3 years ago
13

In the coordinate plane, quadrilateral ABCD has vertices A(-2, 3), B(4,5), C(10, -1), and D(8, -9). Let E, F, G, and H

Mathematics
1 answer:
Aliun [14]3 years ago
4 0

Answer:

 G(3, 1), H(2, 3)

Step-by-step explanation:

When D is the midpoint of EG, it means ...

 D = (E + G)/2

or

 G = 2D -E = 2(3,4) -(3,7) = (2·3-3, 2·4-7) = (3, 1)

Likewise, H is ...

 H = 2D -F = 2(3,4) -(4,5) = (2·3-4, 2·4-5) = (2, 3)

not my answer but i hope it helps you.

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Find the midpoint of segment JP, given J(-4,6) and P(-12,-2).
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Answer:

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<h2>( - 8 , 2)</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

<h3>M = ( \frac{x1 + x2}{2}  ,  \:  \frac{y1 + y2}{2} )</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

J(-4,6) and P(-12,-2)

The midpoint is

<h3>M = ( \frac{ - 4 - 12}{2}  ,  \:  \frac{6 - 2}{2} ) \\  = ( -  \frac{16}{2} ,  \:  \frac{4}{2} )</h3>

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<h3>( - 8 , 2)</h3>

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