Can you guys help me fill this blank?
1 answer:
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Given:
Potential difference between capacitor plates = 2.6 V
Dielectric constant of paper , K = 3.7
Solution:
When air is filled, let the potential difference between capacitor plate be V'
Now, after being disconnected from the battery, the charge stored in the capacitor will remain constant
And when dielectric is introduced between the capacitor plates, the potential difference will be reduced by k times a:
V =
Therfore, V' = KV = 3.7 × 2.6 = 9.62 V
The resulting potential difference of the capacitor, V' = 9.62 V