Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S and q is _____ the force exerted between S and p
a. 1/2
b. 2 times
c. 1/4
d. 4 times
Answer:
4 times
Step-by-step explanation:
Given the following :
Distance between q and S (r) = 1 unit
Distance between P and S (r) = 2 × 1 unit = 2
According to coliumbs law:
F = Ke(q1q2) /r^2
Where F = electrostatic force, Ke = coloumbs constant
q1,q2 = charges, r = distance between two charges
For q and S :
Fsq = Ke(q1q2) / 1^2
Fsq = Ke(q1q2) - - - - - equation 1
For P and S :
Fsp = Ke(q1q2) / 2^2
Fsp = Ke(q1q2) / 4 - - - - - equation 2
Dibiding equation 1 by equation 2
Fsq/Fsp = Ke(q1q2) / Ke(q1q2)/4
Fsq / Fsp = Ke(q1q2) × 4 / Ke(q1q2)
Fsq / Fsp = 4 / 1
Using cross multiplication
Therefore, Fsq = 4 × Fsp
A triangle has 3 sides....each side measuring 0.75 inches...and the perimeter is the total of all 3 sides.
0.75(3) = 2.25 inches
Answer:
Line XY and line MP are co-planar. Which statement shows that the lines are parallel?
A. Line XY and line MP never intersect.
B.Line XY and line MP share the same endpoint.
C.Line XY and line MP intersect at a 90° angle.
D.Line XY and line MP meet at a right angle.
so its a
Step-by-step explanation:
5x^2= 2205
Divide both sides by 5
x^2=441
Find the square root of both sides
x= 21
