Subtract the thickness of the known piece from the total thickness.
Because they have different denominators rewrite them to have the same.
9/32 x 2 = 18/64
Now you have 33/64 - 18/64 = 15/64
The other piece is 15/64 inch thick.
Answer:
x ≈ 4.8
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Trigonometry</u>
- [Right Triangles Only] SOHCAHTOA
- [Right Triangles Only] cos∅ = adjacent over hypotenuse
Step-by-step explanation:
<u>Step 1: Identify Variables</u>
Angle measure = 58°
Adjacent side of angle = <em>x</em>
Hypotenuse = 9
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute [cosine]: cos58° = x/9
- Isolate <em>x</em>: 9cos58° = x
- Evaluate: 4.76927 = x
- Rewrite: x = 4.76927
- Round: x ≈ 4.8
Answer:
none
Step-by-step explanation:
No choice is correct.
The original expression has 560 x 70, the product of 560 and 70 inside the parentheses.
(560 x 70) ÷ 10 is 10 times smaller than 560 x 70
None of the choices show 560 x 70. They show 560 + 70 and 560 - 70.
Answer: none
∫(t = 2 to 3) t^3 dt
= (1/4)t^4 {for t = 2 to 3}
= 65/4.
----
∫(t = 2 to 3) t √(t - 2) dt
= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2
= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du
= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}
= 26/15.
----
For the k-entry, use integration by parts with
u = t, dv = sin(πt) dt
du = 1 dt, v = (-1/π) cos(πt).
So, ∫(t = 2 to 3) t sin(πt) dt
= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt
= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]
= 5/π + 0
= 5/π.
Therefore,
∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.
