Can anyone help me with this question ?
2 answers:
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Answer with Step-by-step explanation:
We are given that if sum of several numbers is odd
We have to prove that at least one of the number is itself odd.
Suppose, we have three numbers
a=6 , b=7,d=8
Sum of numbers=6+7+8=21=Odd number
We know that sum of two odd numbers is always an even number.
Sum of an odd number and an even number is always an odd number.
If we take even odd numbers then sum is always an even number and sum of odd odd numbers then the sum is always an odd number.
Sum of even numbers is always an even number.
Hence, there are atleast one numebr is odd then the sum of several number is odd.
