Answer:
I don't believe so because congruent shapes are exactly the same but a side measurement could be the same on a square and a triangle but those aren't congruent shapes
I hope this helped!
The complete question is
Find the volume of each sphere for the given radius. <span>Round to the nearest tenth
we know that
[volume of a sphere]=(4/3)*pi*r</span>³
case 1) r=40 mm
[volume of a sphere]=(4/3)*pi*40³------> 267946.66 mm³-----> 267946.7 mm³
case 2) r=22 in
[volume of a sphere]=(4/3)*pi*22³------> 44579.63 in³----> 44579.6 in³
case 3) r=7 cm
[volume of a sphere]=(4/3)*pi*7³------> 1436.03 cm³----> 1436 cm³
case 4) r=34 mm
[volume of a sphere]=(4/3)*pi*34³------> 164552.74 mm³----> 164552.7 mm³
case 5) r=48 mm
[volume of a sphere]=(4/3)*pi*48³------> 463011.83 mm³----> 463011.8 mm³
case 6) r=9 in
[volume of a sphere]=(4/3)*pi*9³------> 3052.08 in³----> 3052 in³
case 7) r=6.7 ft
[volume of a sphere]=(4/3)*pi*6.7³------> 1259.19 ft³-----> 1259.2 ft³
case 8) r=12 mm
[volume of a sphere]=(4/3)*pi*12³------>7234.56 mm³-----> 7234.6 mm³
6 times 4 is 24, divided by 2 is 12, minus 1 is 11, plus 5 is 16.
Answer:
In summation form 
Step-by-step explanation:
Within one hour, the first person gives a stack of flyers to six people and within the next hour, those six people give a stack of flyers to six new people.
So, in the first 5 hours, the summation of people that receive a stack of flyers not including the initial person will be given by
6 + (6 × 6) + (6 × 6 × 6) + (6 × 6 × 6 × 6) + (6 × 6 × 6 × 6 × 6).
So, in summation form
Therefore, Sigma-Summation Underscript n = 1 Overscript 5 EndScripts 6 (6) Superscript n minus 1, gives the correct solution. (Answer)
