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PilotLPTM [1.2K]
3 years ago
10

Simplify: (x + 1) (x2-2x + 1)​

Mathematics
1 answer:
hodyreva [135]3 years ago
8 0

Answer:

The answer is = x + 1

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Suppose you observe the number of passengers arriving at a metro station on a shuttle bus that holds up to 8 passengers. Describ
nikitadnepr [17]

Answer:

Sample space can be describes as:

S = {0,1,2,3,4,5,6,7,8}

Step-by-step explanation:

Usually used in probability questions, a sample space is defined as a set of collection of all possible outcomes. It is the list of all possible results.

Sample spaces are usually written using set notation, where each possible outcome is listed only once within curly bracket.

S = {outcome 1, outcome 2, ..........}

As it is given the a bus can hold up to 8 passengers. We need to find the sample space of to number of passengers actually riding the bus.

So the minimum numbers of passengers is 0

The maximum numbers of passengers is 8

So the numbers of passengers lies between 0 and 8.

6 0
3 years ago
Approximately what portion of the box is shaded blue?<br> A.3/5<br> B.2/3<br> C.9/10
BaLLatris [955]

Answer:

I think the answer is C.....

6 0
3 years ago
fair coin is tossed three times. What is the probability that all three tosses land on heads,given that:(a) the first toss lands
maxonik [38]

Answer:

(a) The probability that all three tosses land on heads given that the 1st toss lands on Heads is \frac{1}{4}.

(b) The probability that all three tosses land on heads given that at least one toss lands on heads is \frac{1}{7}.

Step-by-step explanation:

The sample space of tossing 3 coins is:

S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} = 8 outcomes.

(a)

The sample space such that the 1st toss lands on Heads is:

S₁ = {HHH, HHT, HTH, HTT} = 4 outcomes.

The probability that all three tosses land on heads given that the 1st toss lands on Heads is:

P (3 Heads | 1st toss is Heads) = \frac{P(3\ Heads\ \cap \ 1st\ toss\ is\ Heads)}{P(1st\ toss\ is\ Heads)}

                                                  =\frac{\frac{1}{4} }{\frac{4}{8} } \\=\frac{1}{8}\times \frac{8}{4}\\  =\frac{1}{4}

Thus, the probability that all three tosses land on heads given that the 1st toss lands on Heads is \frac{1}{4}.

(b)

The sample space such that at least one toss lands on heads is:

S₂ = {HHH, HHT, HTH, THH, HTT, THT, TTH} = 7 outcomes

The probability that all three tosses land on heads given that at least one toss lands on heads is,

P (3 Heads | At least 1 Heads) =\frac{P(3\ Heads\ \cap\  At\ least\ 1\ Heads)}{P( At\ least\ 1\ Heads)}

                                                  =\frac{\frac{1}{7} }{\frac{7}{8} } \\=\frac{1}{8}\times \frac{8}{7}\\  =\frac{1}{7}

Thus, the probability that all three tosses land on heads given that at least one toss lands on heads is \frac{1}{7}.

4 0
3 years ago
The largest living thing on earth is a California sequoia tree named the “General Sherman”. The diameter of the tree at the base
bearhunter [10]

Answer:

d

Step-by-step explanation:

d

8 0
3 years ago
Ashley is keeping track of the miles she runs over the summer. Her goal is to run 600 miles over the summer. If she has run 230
TEA [102]

Answer:

600-230=L

Step-by-step explanation:

L means Left or What's left

8 0
2 years ago
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