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Semenov [28]
3 years ago
13

4:

Mathematics
1 answer:
KatRina [158]3 years ago
6 0

Answer: 1 Mile

Step-by-step explanation:

In 30 minutes Amy can go 4 miles. It takes Amy 7.5 minutes to get in one mile. The furthest she can go in 12 minutes is one mile.

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How do I write 2sin(0.6)cos(0.6) in one trigonometric function
levacccp [35]
<span>sin(2x)= 2sin(x)cos(x)

can you finish the rest or need more help?

sin(6/5) should be the answer

so we have 2 sin(0.6)cos(0.6)

we know its sin (2x) identity 
x=0.6
so its sin(2*0.6)</span>
4 0
3 years ago
A cube with 2 inch sides is placed on a cube with 3 inch sides. Then a cube with 1 inch sides is placed on the 2 inch cube. What
Taya2010 [7]

Answer:

let's try the "Divide and Conquer" method, that is we break down the problem into pieces and solve each piece until we arrive at the answer.

the formula for the surface area of the cube is:

SA = 6s^2; s is the length of one side of the cube

for the 3-inch cube

SA = 6(3^2)

SA = 6(9)

SA = 54 in^2

note however, that the actual surface area is less the area occupied by the 2-inch cube place on the 3-inch cube, which is

A = s^2; since this is a square

A = 2^2

A = 4 in^2

the actual SA (aSA) therefore of the 3-inch cube is

aSA = 54 - 4 = 50 in^2

for the 2-inch cube

SA = 6s^2

SA = 6(2^2)

SA = 6(4)

SA = 24 in^2

to solve for the actual SA of the 2-inch cube, we subtract the area which is in contact with the 3-inch cube and the 1-inch cube

aSA = 24 - 2^2 - 1^2

aSA = 24 - 4 - 1

aSA = 19 in^2

for the 1-inch cube

SA = 6s^2

SA = 6(1^2)

SA = 6 in^2

the actual surface area is less the area in contact with the 2-inch cube

aSA = 6 - 1^2

aSA = 5 in^2

the surface area of the three cube tower will just be the sum of the aSA of the three cubes

SA = 50 + 19 + 5

SA = 74 in^2   ans

Step-by-step explanation:

5 0
3 years ago
How would you write 8^5 as a multiplication expression? A. 8 × 5 B. 8 × 8 × 8 × 8 × 8 C. 5 × 5 × 5 × 5 × 5 × 5 × 5 × 5
Neporo4naja [7]

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

<u>if </u><u>we </u><u>ever </u><u>face </u><u>a </u><u>number </u><u>written </u><u>in </u><u>the </u><u>form </u><u>of </u>\underline{x^{n}}<u>where </u><u>x </u><u>denotes </u><u>the </u><u>base </u><u>and </u><u>n </u><u>denotes </u><u>the </u><u>exponent</u><u> </u><u>or </u><u>power </u><u>,</u><u> </u><u>we </u><u>can </u><u>expand </u><u>it </u><u>in </u><u>the </u><u>following</u><u> </u><u>way </u><u>-</u>

x^{n} = x \times x \times x \times.... x ( upto\: " n " \: times )

therefore ,

8 {}^{5}  = 8 \times 8 \times 8 \times 8 \times 8

option ( B )

hope helpful -,-

4 0
2 years ago
Read 2 more answers
Changing the value of b in results in a _____ of the graph.
Nataliya [291]
Changing B changes where it crosses on the y-axis... on the graph
8 0
3 years ago
A probability experiment is conducted in which the sample space of the experiment is Sequals=StartSet 9 comma 10 comma 11 comma
White raven [17]

Answer:

From both approaches P(F or G)=0.667

Step-by-step explanation:

P(F or G)=?

F={9, 10, 11, 12, 13}​

G={13,14,15,16}

Finding P(F or G) by counting outcomes in F or G

F or G={9, 10, 11, 12, 13}or {13,14,15,16}

F or G={9, 10, 11, 12,13,14,15,16}

number of outcomes in F or G=n(F or G)=8

S={9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20}​

number of outcomes in S=n(S)=12

P(F or G)=n(F or G)/n(S)

P(F or G)=8/12

P(F or G)=0.667

Finding P(F or G) by addition rule

P(F or G)=P(F)+P(G)-P(F and G)

F={9, 10, 11, 12, 13}​

number of outcomes in F=n(F)=5

P(F)=n(F)/n(S)

P(F)=5/12

P(F)=0.417

G={13,14,15,16}

number of outcomes in G=n(G)=4

P(G)=n(G)/n(S)

P(G)=4/12

P(G)=0.333

F and G={9, 10, 11, 12, 13}and {13,14,15,16}

F and G={13}

number of outcomes in F and G=n(F and G)=1

P(F and G)=n(F and G)/n(S)

P(F and G)=1/12

P(F and G)=0.083

P(F or G)=P(F)+P(G)-P(F and G)

P(F or G)=0.417+0.333-0.083

P(F or G)=0.667

8 0
2 years ago
Read 2 more answers
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