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4 years ago

Simplify completely. (w15w5)4m need help please

2 answers:

5 0

(w15w5)4m is the same as

4m(15w•5w)

This is because w•15 is still 15w and w•5 is still 5w, it’s just a way of organizing it!!! And it doesn’t matter if the 4m is behind or in front of the (w15w5) because you still distribute normally!

Now let’s distribute!

But wait, there has to be order of operations here !!!
PEMDAS

So let’s do 15w•5w which equals 75w^2 since 15•5 is 75 and when you are multiplying two variables together you get the variable, squared because w•w=w^2

Think of it as 2•2=4 which is 2^2!!!

So then we are left with 4m•75w^2 which is

300mw^2 this is because when you are multiplying two unknown variables you have to make them join together, so first let’s multiply the coefficients(the real numbers)!

75•4=300

then m•w^2 which is just mw^2!!

So the final answer is 300mw^2!!

Please give me brainliest, if you need any further help, please just tell me!!! If you need to contact me for further support add me on ig

@jessmyybest

Komok [63]4 years ago

3 0

Answer:

w40

Step-by-step explanation:

just took the test, hope this helps!!!

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Please solve with steps.

Kitty [74]

Answer: a) h = 2

b) a = $-\dfrac{3}{4}$ k = $\bold{3\dfrac{1}{2}}$

Step-by-step explanation:

The vertex form of a quadratic equation is: y = a(x - h)² + k where

a is the vertical stretch
(h, k) is the vertex

The graph shows the axis of symmetry at x = 2, therefore, the x-coordinate of the vertex (h) is 2.

Two points are given: $\bigg(0, \dfrac{1}{2}\bigg)\ and\ \bigg(3, 2 \dfrac{3}{4}\bigg)$ . We can use these points to create two equations and then solve the system to find the a and k-values.

y = a(x - 2)² + k

$\bigg(0, \dfrac{1}{2}\bigg)\\\rightarrow \dfrac{1}{2}=a(0-2)^2+k\\\\\rightarrow \dfrac{1}{2}=4a+k\\\\\rightarrow \dfrac{1}{2}-4a=k\\\\\\\bigg(3, 2\dfrac{3}{4}\bigg)\\\rightarrow 2\dfrac{3}{4}=a(3-2)^2+k\\\\\rightarrow 2\dfrac{3}{4}=a+k\\\\\rightarrow 2\dfrac{3}{4}-a=k\\\\\\\\\dfrac{1}{2}-4a=2\dfrac{3}{4}-a\\\\\dfrac{1}{2}-2\dfrac{3}{4}=4a-a\\\\\dfrac{2}{4}-\dfrac{11}{4}=3a\\\\-\dfrac{9}{4}=3a\\\\-\dfrac{9}{4\cdot 3}=\dfrac{3a}{3}\\\\ \bold{-\dfrac{3}{4}=a}$

Solve for k:

$2\dfrac{3}{4}-a=k\\\\\\2\dfrac{3}{4}-\bigg(-\dfrac{3}{4}\bigg)=k\\\\\\\bold{3\dfrac{1}{2}=k}$

5 0

3 years ago

The equation of line CD is (y−3) = − 2 (x − 4). What is the slope of a line perpendicular to line CD?

alexdok [17]

$(y-3)=-2(x-4) \\ y-3 = -2x+8 \\ y=-2x+11$
Slope: -2

NOTE: The line perpendicular to line $y=mx+b$ has a slope $-\dfrac{1}{m}$ .

So your slope is $-\dfrac{1}{-2}=\dfrac{1}{2}$ - 1 over 2 (Answer a)

4 0

3 years ago

HELP PLEASEEE What is 1/6 of 24?

Semmy [17]

Answer:4

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What are the solutions of the equation x^6-9x^3+8= 0 use u substitution to solve

labwork [276]

Answer: x = {1, 2}

Step-by-step explanation:

x⁶ - 9x³ + 8 = 0

Let u = x³

⇒ (x³)² - 9(x³)¹ + 8(x³)⁰ = 0

⇒ u² - 9u + 8 = 0

⇒ (u - 1)(u - 8) = 0

⇒ u = 1 or u = 8

Replace u with x³

x³ = 1 or x³ = 8

Take the cubed root of each side

x = 1 or x = 2

7 0

3 years ago

The topic is law of cosines and sines and I need help with this

sergiy2304 [10]

Answer:

Answer is 2nd one (20.8)

5 0

3 years ago