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3 years ago

Find the area of rectangle ,semicircle and the figure

Mathematics

1 answer:

ExtremeBDS [4]3 years ago

3 0

Step-by-step explanation:

Srectangle=21*30=630cm^2

Ssemicircle=(11.5^2*pi)/2=132.25pi/2=66.125cm^2*pi

Sfigure=630cm*2+2*66.125cm^2*pi=630cm^2+pi*132.25pi

if we assume that pi=3.14

Sfigure=630cm^2+415.265cm^2=1045.265cm^2

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The sum of three consecutive even numbers is 120. what is the smallest of the three numbers

nlexa [21]

Think it this way. 120/3=40. you need three consecutive numbers, which means those numbers are n1+n2+n3=120 and middle number n2 is gotten by dividing the number 120 with how many numbers you sum, in this case 3. the smaller number n1 is n2-1 and bigger n3 is n2+1
n1=40-1
n2=40+0
n3=40+1

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3 years ago

One month Ahmad rented 3 movies and 2 video games for a total of $22. The next month he rented 5 movies and 6 video games for a

Hitman42 [59]

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3 years ago

Graph the solution on a number line -6x+3>-39

SCORPION-xisa [38]

Step-by-step explanation:

$-6x+3>-39\qquad\text{subtract 3 from both sides}\\\\-6x+3-3>-39-3\\\\-6x>-42\qquad\text{change the all signs}\\\\6x$

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3 years ago

Answer the following question about the function whose derivative is given below

Komok [63]

Answer:

a) The critical points are $x = 3$ and $x = -6$ .

b) f is decreasing in the interval $(-\infty, -6)$

f is increasing in the intervals $(-6,3)$ and $(3,\infty)$ .

c) Local minima: $x = -6$

Local maxima: No local maxima

Step-by-step explanation:

(a) what are the critical points of f?

The critical points of f are those in which $f^{\prime}(x) = 0$ . So

$f^{\prime}(x) = 0$

$(x-3)^{2}(x+6) = 0$

So, the critical points are $x = 3$ and $x = -6$ .

(b) on what intervals is f increasing or decreasing? (if there is no interval put no interval)

For any interval, if $f^{\prime}$ is positive, f is increasing in the interval. If it is negative, f is decreasing in the interval.

Our critical points are $x = 3$ and $x = -6$ . So we have those following intervals:

$(-\infty, -6), (-6,3), (3, \infty)$

We select a point x in each interval, and calculate $f^{\prime}(x)$ .

-------------------------

$(-\infty, -6)$

$f^{\prime}(-7) = (-7-3)^{2}(-7+6) = (100)(-1) = -100$

f is decreasing in the interval $(-\infty, -6)$

---------------------------

$(-6,3)$

$f^{\prime}(2) = (2-3)^{2}(2+6) = (1)(8) = 8$

f is increasing in the interval $(-6,3)$ .

------------------------------

$(3, \infty)$

$f^{\prime}(4) = (4-3)^{2}(4+6) = (1)(10) = 10$

f is increasing in the interval $(3,\infty)$ .

(c) At what points, if any, does f assume local maximum and minima values. ( if there is no local maxima put mo local maxima) if there is no local minima put no local minima

At a critical point x, if the function goes from decreasing to increasing, it is a local minima. And if the function goes from increasing to decreasing, it is a local maxima.

So, for each critical point is this problem:

At $x = -6$ , f goes from decreasing to increasing.

So $x = -6$ , f assume a local minima value

At $x = 3$ , f goes from increasing to increasing. So, there it is not a local maxima nor a local minima. So, there is no local maxima for this function.

4 0

3 years ago

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AleksandrR [38]

Answer:

Then go on a dating app not a study app

Step-by-step explanation:

3 0

3 years ago

Find the area of rectangle ,semicircle and the figure​

Find the area of rectangle ,semicircle and the figure