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stepladder [879]
3 years ago
13

Solve for y: x(y-3)=2y+1

Mathematics
2 answers:
polet [3.4K]3 years ago
7 0

Answer: y=(3x+1)/(x-2)

Step-by-step explanation: Step by step with principles included in the image.

lana [24]3 years ago
6 0

Answer:

y =  \frac{3x + 1}{x - 2}

Step-by-step explanation:

Add -2y to both sides:

xy−3x+<u>−2y</u>=2y+1+<u>−2y</u>

Simplify:

xy−3x−2y=1

Add 3x to both sides:

xy−3x−2y+<u>3x</u>=1+<u>3x</u>

Simplify:

xy−2y=3x+1

Factor out variable y:

y(x−2)=3x+1

Divide both sides by x-2:

\frac{y(x - 2)}{x - 2}  =  \frac{3x + 1}{x - 2}

Simplify:

y =  \frac{3x + 1}{x - 2}

Hope this helps :)

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3 0
3 years ago
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
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Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

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7 0
3 years ago
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