The cost of children’s ticket is $ 5
<h3><u>Solution:</u></h3>
Let "c" be the cost of one children ticket
Let "a" be the cost of one adult ticket
Given that adult ticket to a museum costs 3$ more than a children’s ticket
<em>Cost of one adult ticket = 3 + cost of one children ticket</em>
a = 3 + c ------ eqn 1
<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>
200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100
200a + 100c = 2100 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
Substitute eqn 1 in eqn 2
200(3 + c) + 100c = 2100
600 + 200c + 100c = 2100
600 + 300c = 2100
300c = 1500
<h3>c = 5</h3>
Thus the cost of children’s ticket is $ 5
Answer:
C: H <u>> </u> 60
Step-by-step explanation:
H is 60 in or taller, underlined indicates that it's also 60 in, not just above it.
The sum of the interior angles of a quadrilateral -(4 sided shape)
its 360 degrees
add up all the angles, set it equal to 360 degrees, solve for x
any questions
Solve all of the equations below and add all of the solutions to those equations to get your answer.
10x4x2=
8x4x2=
10x8=
(10x8)-(7x6)=
7x2x2=
6x2x2=
7x6=
Answer:
43.6 amp
Step-by-step explanation:
Given
A 40 amp fuse carries a temporary 9 % current overload.
9% current overload means that whatever will be the normal current carrying capacity of fuse, during overload it carries 9% more than that.
Current carrying capacity of fuse is 40 amp.
during overload it carries 9% more
over load current = 9% of 40 amp = 9/100 *40 = 3.6 amp
total current flowing through fuse during overload = 40 amp + 3.6 amp
= 43.6 amp (answer)