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const2013 [10]
3 years ago
10

Help me pleasee just find the total area and how to do it

Mathematics
2 answers:
schepotkina [342]3 years ago
6 0

Answer:

total area 40cm

Step-by-step explanation:

the find the area of the rectangle u multiply the two sides.

the area of a triangle is base x height divided by 2.

formula would be

l x w + ((b x h)/2)

netineya [11]3 years ago
4 0

Answer:

40cm Total

Step-by-step explanation:

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NNADVOKAT [17]

Answer:

y =7 i think. idk im bad at math sorry. lol

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4 years ago
What is the surface area of the rectangular prism below? 8 19 8​
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The answer is c because S=Ph+2b
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3 years ago
A charity receives 2025 contributions. Contributions are assumed to be mutually independent and identically distributed with mea
uysha [10]

Answer:

The 90th percentile for the distribution of the total contributions is $6,342,525.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums of size n, the mean is \mu*n and the standard deviation is s = \sqrt{n}*\sigma

In this question:

n = 2025, \mu = 3125*2025 = 6328125, \sigma = \sqrt{2025}*250 = 11250

The 90th percentile for the distribution of the total contributions

This is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. Then

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

1.28 = \frac{X - 6328125}{11250}

X - 6328125 = 1.28*11250

X = 6342525

The 90th percentile for the distribution of the total contributions is $6,342,525.

3 0
3 years ago
PLEASE ANSWER THIS QUESTION RIGHT Name the x-intercept(s)?<br> A:0 and 4,B:2,C:4,D:0.
harina [27]

Answer:

A. 0 and 4

Step-by-step explanation:

The x-intercepts are simply the values of x when y = 0. In other words it is the points where the line curve intercepts or cuts across the x-axis.

Form the graph given, we can see that at x = 0 and x = 4, the value of y = 0. Simply put, the curve cuts the x-axis at x = 0 and x = 4.

x-intercepts are 0 and 4.

7 0
3 years ago
Find all of the eigenvalues λ of the matrix A. (Hint: Use the method of Example 4.5 of finding the solutions to the equation 0 =
Svetradugi [14.3K]

Answer:

\lambda=8,\ \lambda=-5

Step-by-step explanation:

<u>Eigenvalues of a Matrix</u>

Given a matrix A, the eigenvalues of A, called \lambda are scalars who comply with the relation:

det(A-\lambda I)=0

Where I is the identity matrix

I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix is given as

A=\left[\begin{array}{cc}3&5\\8&0\end{array}\right]

Set up the equation to solve

det\left(\left[\begin{array}{cc}3&5\\8&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda \end{array}\right]\right)=0

Expanding the determinant

det\left(\left[\begin{array}{cc}3-\lambda&5\\8&-\lambda\end{array}\right]\right)=0

(3-\lambda)(-\lambda)-40=0

Operating Rearranging

\lambda^2-3\lambda-40=0

Factoring

(\lambda-8)(\lambda+5)=0

Solving, we have the eigenvalues

\boxed{\lambda=8,\ \lambda=-5}

8 0
4 years ago
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