16 - 5(3t - 4) = 8(-2t + 11) <em>use distributive property</em>: <em>a(b + c) = ab + ac</em>
16 - (5)(3t) - (5)(-4) = (8)(-2t) + (8)(11)
16 - 15t + 20 = -16t + 88
36 - 15t = -16t + 88 <em>subtract 36 from both sides</em>
-15t = -16t + 52 <em>add 16t to both sides</em>
t = 52
Answer:
{0,6}
Step-by-step explanation:
-2x^2+12x = 0
Factor out a -2x
-2x(x-6) =0
Using the zero product property
-2x = 0 and x-6=0
-2x = 0
Divide by -2
-2x/-2 = 0/-2
x=0
x-6=0
Add 6 to each side
x-6+6 =0+6
x=6
The solutions are 0 and 6
Answer:
Step-by-step explanation:
First confirm that x = 1 is one of the zeros.
f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26
f(1) = 2 - 14 + 38 - 26
f(1) = -12 + 38 = + 26
f(1) = 26 - 26
f(1) = 0
=========================
next perform a long division
x -1 || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26
2x^3 - 2x^2
===========
-12x^2 + 28x
-12x^2 +12x
==========
26x -26
26x - 26
========
0
Now you can factor 2x^2 - 12x + 26
2(x^2 - 6x + 13)
The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16
So you are going to get a complex result.
x = -(-6) +/- sqrt(-16)
=============
2
x = 3 +/- 2i
f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)
The zeros are
1
3 +/- 2i
Answer:
x ≈ 14.57
Step-by-step explanation:
using the sine ratio in the right triangle
sin59° = 
= 
( multiply both sides by 17 )
17 × sin59° = x , then
x ≈ 14.57 ( to 2 dec. places )
Answer:
The surrender of Detroit
Step-by-step explanation:
The other two were american victories, the surrender of Detroit was a Indian/British victory and an early one in the war
