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Citrus2011 [14]
3 years ago
8

This question is really confusing me, it talks about unknown angle problems with Algebra.

Mathematics
2 answers:
ankoles [38]3 years ago
7 0

Answer:

x=20

Step-by-step explanation:

The two angles are complementary angles.  Complementary angles add to 90 degrees

x + 3x+10 = 90

Combine like terms

4x+10 = 90

Subtract 10 from each side

4x+10-10 = 90-10

4x= 80

Divide each side by 4

4x/4 = 80/4

x = 20

Sever21 [200]3 years ago
3 0

Answer:

20

Step-by-step explanation:

The two given and marked angles add up to 90.

A = x

B = 3x + 10

A + B = 90          Substitute for A and B. A and B are just letters I gave things.

x + 3x + 10 = 90        Combine the left

4x + 10 = 90              Subtract 10 from both sides.

4x +10-10 = 90-10     Combine

4x = 80                      Divide by 4

4x/4=80/4

x = 20

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The problem is 3+6x = 15 with x being the number of white numbers.
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The number of white marbles is 2.
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3 years ago
A bag contains marbles: 5 red, 2 blue, and 1 green. You pick a marble and then another one without replacement. What is the prob
max2010maxim [7]

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1st draw: green

2/12. (2 green out of 12 marbles), reduces to 1/6

2nd draw: blue

4/11 (4 blue marbles out of the 11 marbles remaining after 1st draw.)

Probability of theses BOTH happening: multiply these individual probabilities.

Conditional probability:

P(a and b) = P(a)P(b|a)

Prob(event 1) × Prob(event 2 given event 1).

1/6 • 4/11 = 4/66 = 2/33 or 0.0606. just a hair over 6% probability of the described sequence hapening.

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2 years ago
What other information do you need in order to prove the triangles congruent using the SAS congruence postulate
iren [92.7K]

AC is perpendicular to BD.

<h3>Further explanation</h3>
  • We observe that both the ABC triangle and the ADC triangle have the same AC side length. Therefore we know that \boxed{ \ \overline{AC} \cong \overline{AC} \ } is reflexive.
  • The length of the base of the triangle is the same, i.e., \boxed{ \ \overline{BC} = \overline{CD} \ }.
  • In order to prove the triangles congruent using the SAS congruence postulate, we need the other information, namely \boxed{ \ AC \bot BD \ }. Thus we get ∠ACB = ∠ACD = 90°.

Conclusions for the SAS Congruent Postulate from this problem:

  • \boxed{ \ \overline{BC} = \overline{CD} \ }
  • ∠ACB = ∠ACD
  • \boxed{ \ \overline{AC} = \overline{AC} \ }

- - - - - - - - - -

The following is not other or additional information along with the reasons.

  • ∠CBA = ∠CDA no, because that is AAS with ∠ACB = ∠ACD and \boxed{ \ \overline{AC} \cong \overline{AC} \ }
  • ∠BAC = ∠DAC no, because that is ASA with \boxed{ \ \overline{AC} \cong \overline{AC} \ } and ∠ACB = ∠ACD.
  • \boxed{ \ \overline{BC} = \overline{CD} \ } no, because already marked.

- - - - - - - - - -

Notes

  • The SAS (Side-Angle-Side) postulate for the congruent triangles: two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle; the included angle properly represents the angle formed by two sides.
  • The ASA (Angle-Side-Angle) postulate for the congruent triangles: two angles and the included side of one triangle are congruent to two angles and the included side of another triangle; the included side properly represents the side between the vertices of the two angles.  
  • The SSS (Side-Side-Side) postulate for the congruent triangles: all three sides in one triangle are congruent to the corresponding sides within the other.
  • The AAS (Angle-Angle-Side) postulate for the congruent triangles: two pairs of corresponding angles and a pair of opposite sides are equal in both triangles.  
<h3>Learn more</h3>
  1. Which shows two triangles that are congruent by ASA?  brainly.com/question/8876876  
  2. Which shows two triangles that are congruent by AAS brainly.com/question/3767125
  3. About vertical and supplementary angles brainly.com/question/13096411  
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Jamie and Stella are saving money to sign up for a school trip to Washington, D.C. In order to sign up for the trip, they must p
sveticcg [70]

Answer:

  •    Part 1: 25x ≥ 600
  •    Part 2: 15y ≥ 600
  •    Part 3: y ≤ 40

Explanation:

Verbal statements must be translated into algebraic expressions, equations or inequalities.

<u>1. Money earned by Jamie washing cars for $25 each</u>

   Let x represent the number of cars Jaime washes.

  •    25x

<u>2. Money earned by Stella  making pecan pies for $15 each</u>

   Let y represent the number of pies she makes

  •    15y

<u>3. Constraint on the number of pies that Stella can make because she only has enough supplies to make 40 pies</u>.

Write an inequality using the symbol ≤, since y can take any integer value up to 40.

  •    y ≤ 40

4. First question:

Part 1: Write a constraint (an inequality) to represent how much money Jamie needs for his trip

  •    25x ≥ 600

5. Second question:

Part 2: Write a constraint (an inequality) to represent how much money Stella needs for her trip.

  •    15y ≥ 600

6. Third question

Part 3: Write a constraint (an inequality) to represent the limitations of Stella's supplies.

From step # 3

  •    y ≤ 40

7. Conclusion

You can solve the inequalities fo find whether Stella can or not afford the trip:

Solve for the inequalities that represent Stella's situation:

  •  15y ≥ 600
  •    y ≥ 600 / 15
  •    y ≥ 40
  •    From step 6: y ≤ 40

The solution set is the intersection of the two solutions:

  • y ≥ 40 ∩ y ≤ = 40 = 40.

  • Interpretation: Stella will be able to make 40 pies, which represents a revenue of $ 15 / pie × 40 pie = $ 600, so she will be able to make the trip.

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Answer:

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