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4 years ago

11

H=-16t^2 + 104t + 56

1 answer:

WITCHER [35]4 years ago

8 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$h=-16t^{2}+104t+56$

Using a graphing tool

see the attached figure

This is the equation of a vertical parabola open downward

The vertex is the point (3.25,225) (a maximum)

The zero's of the function or the t-intercepts are the points (-0.5,0) and (7,0)

The h-intercept of the function is the point (0,56)

The domain of the function are all real numbers

The range of the function $h\leq225$ ----> All real numbers less than or equal to 225

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Syrus is buying a tent with the dimensions shown below. The volume inside the tent is 363636 feet^3 3 cubed. Syrus isn't sure if

stealth61 [152]

Answer:

The height of the tent = 3 feet

Step-by-step explanation:

Question

Syrus is buying a tent with the dimensions shown below. The volume inside the tent is 36 feet^3. Syrus isn't sure if the tent will be tall enough for him to sit up inside. The tent is the shape of triangular prism whose length is 6 feet and width is 4 feet. What is the height of the tent?

Given:

Length of the tent = 6 feet

Width of the tent = 4 feet

Volume of the tent = 36 $feet^3$

To find the height of the tent.

Solution:

Since the ten is in shape of triangular prism, so the volume of traingular prism is given as:

$V=\frac{1}{2}\times l\times w\times h$

where $l$ represents length, $w$ represents width and $h$ represents height of the prism.

Plugging in the know values of the dimension of the tent and the volume to find the height of the tent.

$36=\frac{1}{2}\times 6\times 4\times h$

Simplifying.

$36=12h$

Dividing both sides by 12.

$\frac{36}{12}=\frac{12h}{12}$

$3=h$

∴ $h=3$

Thus, the height of the tent = 3 feet

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stealth61 [152]

Answer:

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Step-by-step explanation:

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