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aniked [119]
3 years ago
9

Round this number to the nearest thousandth 0.634759

Mathematics
2 answers:
Romashka [77]3 years ago
7 0

Answer:

0.63

Step-by-step explanation:

Only 0.634 matters. If the thousandths place is 5 or greater, it'd be 0.64

fenix001 [56]3 years ago
7 0

Answer: 0.635

Step-by-step explanation: the number 7 rounds up so it makes the four move up to a five

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Step-by-step explanation:

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3 years ago
The number of defective circuit boards coming off a soldering machine follows a Poisson distribution. During a specific ten-hour
Alexus [3.1K]

Answer:

a) the probability that the defective board was produced during the first hour of operation is \frac{1}{10} or 0.1000

b) the probability that the defective board was produced during the  last hour of operation is \frac{1}{10} or 0.1000

c) the required probability is 0.2000

Step-by-step explanation:

Given the data in the question;

During a specific ten-hour period, one defective circuit board was found.

Lets X represent the number of defective circuit boards coming out of the machine , following Poisson distribution on a particular 10-hours workday which one defective board was found.

Also let Y represent the event of producing one defective circuit board, Y is uniformly distributed over ( 0, 10 ) intervals.

f(y) = \left \{ {{\frac{1}{b-a} }\\\ }} \right   _0;   ( a ≤ y ≤ b )_{elsewhere

= \left \{ {{\frac{1}{10-0} }\\\ }} \right   _0;   ( 0 ≤ y ≤ 10 )_{elsewhere

f(y) = \left \{ {{\frac{1}{10} }\\\ }} \right   _0;   ( 0 ≤ y ≤ 10 )_{elsewhere

Now,

a) the probability that it was produced during the first hour of operation during that period;

P( Y < 1 )   =   \int\limits^1_0 {f(y)} \, dy

we substitute

=    \int\limits^1_0 {\frac{1}{10} } \, dy

= \frac{1}{10} [y]^1_0

= \frac{1}{10} [ 1 - 0 ]

= \frac{1}{10} or 0.1000

Therefore, the probability that the defective board was produced during the first hour of operation is \frac{1}{10} or 0.1000

b) The probability that it was produced during the last hour of operation during that period.

P( Y > 9 ) =    \int\limits^{10}_9 {f(y)} \, dy

we substitute

=    \int\limits^{10}_9 {\frac{1}{10} } \, dy

= \frac{1}{10} [y]^{10}_9

= \frac{1}{10} [ 10 - 9 ]

= \frac{1}{10} or 0.1000

Therefore, the probability that the defective board was produced during the  last hour of operation is \frac{1}{10} or 0.1000

c)

no defective circuit boards were produced during the first five hours of operation.

probability that the defective board was manufactured during the sixth hour will be;

P( 5 < Y < 6 | Y > 5 ) = P[ ( 5 < Y < 6 ) ∩ ( Y > 5 ) ] / P( Y > 5 )

= P( 5 < Y < 6 ) / P( Y > 5 )

we substitute

 = (\int\limits^{6}_5 {\frac{1}{10} } \, dy) / (\int\limits^{10}_5 {\frac{1}{10} } \, dy)

= (\frac{1}{10} [y]^{6}_5) / (\frac{1}{10} [y]^{10}_5)

= ( 6-5 ) / ( 10 - 5 )

= 0.2000

Therefore, the required probability is 0.2000

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3 years ago
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andrew11 [14]

Answer:

 A. coefficients: 70, 12; variables: x, y.

 B. 2 terms: 70x, 12y; separated by an addition symbol

 C. 70x

Step-by-step explanation:

We will answer the questions in the context of this problem. In other problems, the meaning of "coefficient", "variable", and "term" may be different.

__

A. The coefficients are the numbers; the variables are the letters. Then the coefficients are 70 and 12; the variables are x and y.

__

B. Each product is a term. Terms are separated by the + sign. There are two terms in this expression, one on either side of the + sign. When an expression is written with no parentheses, the terms are separated by + or - signs. (Often, we think of the minus sign as being part of the coefficient of the term. Then we can say terms are separated by + signs. 10x + (-32y), for example.)

__

C. When you match the coefficients to the numbers in the problem statement, you see that the number matching the earnings at the diner is $70 per shift. If we assume that x represents the number of shifts worked at the diner, then the term 70x will represent the total earned from the diner. It is the product of the earnings per shift and the number of shifts.

Read more on Brainly.com - brainly.com/question/13474804#readmore

3 0
3 years ago
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