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WINSTONCH [101]

3 years ago

6

Help please!! Write the equation of the line fully simplified slope-intercept form.

1 answer:

Kisachek [45]3 years ago

4 0

Answer:

y=mxtb right? so... y= 0+8

Step-by-step explanation:

i think so right? im sorry if im wrong

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Cos y/ 1-sin y= 1+sin y/cos y. Verify the identity. Show All Steps!

Vlada [557]

Answer:

When proving identities, the answer is in the explanation.

Step-by-step explanation:

$\frac{\cos(y)}{1-\sin(y)}$

I have two terms in this denominator here.

I also know that $1-\sin^2(\theta)=\cos^2(theta)$ by Pythagorean Identity.

So I don't know how comfortable you are with multiplying this denominator's conjugate on top and bottom here but that is exactly what I would do here. There will be other problems will you have to do this.

$\frac{\cos(y)}{1-\sin(y)} \cdot \frac{1+\sin(y)}{1+\sin(y)}$

Big note here: When multiplying conjugates all you have to do is multiply fist and last. You do not need to do the whole foil. That is when you are multiplying something like $(a-b)(a+b)$ , the result is just $a^2-b^2$ .

Let's do that here with our problem in the denominator.

$\frac{\cos(y)}{1-\sin(y)} \cdot \frac{1+\sin(y)}{1+\sin(y)}$

$\frac{\cos(y)(1+\sin(y))}{(1-\sin(y))(1+\sin(y)}$

$\frac{\cos(y)(1+\sin(y))}{1^2-\sin^2(y)}$

$\frac{\cos(y)(1+\sin(y))}{1-\sin^2(y)}$

$\frac{\cos(y)(1+\sin(y))}{cos^2(y)}$

In that last step, I apply the Pythagorean Identity I mentioned way above.

Now You have a factor of cos(y) on top and bottom, so you can cancel them out. What we are really saying is that cos(y)/cos(y)=1.

$\frac{1+\sin(y)}{cos(y)}$

This is the desired result.

We are done.

6 0

3 years ago

WILL GIVE EXTRA BRAINLST <br><br> HAVE A NICE DAy

Juli2301 [7.4K]

Answer: 1.) Irrational (because its not terminal)

2.) $2^{2}$

8 0

3 years ago

Diego is solving the inequality 100 − 3x ≥ -50. He solves the equation 100 − 3x = -50 and gets x = 50. What is the solution to t

ZanzabumX [31]

Answer:

x≤50

Step-by-step explanation:

100-3x≥-50

subtracting 100 at both side on inequality

-100+100-3x≥--50-100

-3x≥-150

Dividing both sides by 3

-3x/3≥-150/3

-x≥--50

Adding 50 on both sides

-x+50≥-50+50

-x+50≥0

Adding x on both sides

-x+x+50≥0+x

50≥x

so,

x≤50

7 0

3 years ago

Read 2 more answers

Find an equation of the line through (2,6) and parallel to y=2x+3

Setler [38]

Step-by-step explanation:

We first Find the Slope of the line y=2x+3

The Slope Intercept Form of the equation of a given line is:

y=mx+c

where m is the Slope of that line, and c is the Y intercept.

For this line, the Slope is 2

So the Slope of the line PARALLEL to y=2x+3 will also be 2. And we are given that it passes through the point (2,6)

The Point-Slope form of the Equation of a Straight Line is:

(y−k)=m⋅(x−h)

m is the Slope of the Line

(h,k) are the co-ordinates of any point on that Line.

Here, we have been given the coordinates (h,k) of 1 point on that line as (2,6)

And the Slope m is 2

Substituting the values of h,k and m in the Point-Slope form, we get

(y−2)=(2)⋅(x−6)

(y−2)=2⋅(x-6)

y−2=2x -12

y=2x -12 +2

y=2x-10

The graph will look like

graph{y=2x -10 10 [10, -10, 5, - 5]}

3 0

3 years ago

Help me, please !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

erica [24]

Answer:

The first one is the answer

3 0

3 years ago