1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elis [28]
4 years ago
11

What are the real and complex solutions of the polynomial equation? x^4-41x^2=-400

Mathematics
1 answer:
tankabanditka [31]4 years ago
7 0
<h3>Answer:</h3>

The real solutions are -5, -4, 4, 5. There are no complex solutions.

<h3>Step-by-step explanation:</h3>

The equation ...

... x^4 -41x^2 +400 = 0

can be factored as ...

... (x^2 -16)(x^2 -25) = 0

... (x -4)(x +4)(x -5)(x +5) = 0

So, all roots are real and are ...

... x ∈ {-5, -4, 4, 5}

_____

These are the values of x that make the factors zero.

You might be interested in
If no vertical line intersects the graph of a relation in more than one point, then the relation is a function.
ki77a [65]
If I'm understanding this correctly you mean:
If a vertical line does not connect to more than one point in a relation then that relation is a function.
Then your answer is A-True.
That is called the vertical line test. The vertical line cannot touch more than one point at the same time if it is a function. If it does touch then it is not a function.
7 0
4 years ago
Find the value of x. Round your answer to the nearest tenth.
natka813 [3]

That's a question about the Pythagorean Theorem.

We use the Pythagorean Theorem to find the value of one side in a right triangle.

This theorem says that:

\boxed{a^2 = b^2 + c^2}

  • <em>a</em> is the hypotenuse (It's the opposite side the right angle).
  • <em>b</em> and <em>c </em>are cathetus (They're the adjacent sides the right angle).

Okay, now, let's go to solve this problem! In our figure, we have two cathetus. Their values are 10 and 7 and we have to find the value of <em>x </em>(the hypotenuse). Let's change this information in that formula.

a^2 = b^2 + c^2\\x^2 = 10^2 + 7^2\\x^2 = 100 + 49\\x^2 = 149\\x = \sqrt{149}

Therefore, the value of <em>x </em>is \sqrt{149}.

I hope I've helped. :D

Enjoy your studies! \o/

5 0
3 years ago
I need help understanding angle relationships! I just need a clear and simple explanation so someone as dumb as me can understan
LiRa [457]
This helped me i hope it helps you if not check out this link.
https://www.khanacademy.org/math/geometry-home/geometry-angles/geometry-vert-comp-supp/v/vertical-ad... 

3 0
3 years ago
Can someone please help me with this
Murljashka [212]
The answer is:  [C]:  "  2/3, 6/9, 8/12 " .
____________________________________________
4 0
4 years ago
Read 2 more answers
100<br> 200<br> 300<br> 400 500 600 700<br> Quantity Supplied<br> nstructions: Refer to the graph and answer the questions below
mash [69]

Answer:

a. 400

b. 4$

Step-by-step explanation:

2$ equals 0 Quantity

3$ equals 100 Quantity

4$ equals 200 Quantity

We can see that starting from 2$, a dollar will increase the Quantity by 100

7 0
2 years ago
Other questions:
  • 10 - 8(2x - 7) Rewrite the expression using properties
    15·1 answer
  • Can someone help me answer and explain how to solve this?
    13·2 answers
  • Can someone help me out?
    7·2 answers
  • Which equation can be represented using the number line?​
    8·2 answers
  • A 12 pack of cinnamin scented pencils sells for $3.00 at a school booster club sale .what is the sales tax rate if the total cos
    6·1 answer
  • What’s is CA?? That’s only I really need for this question
    6·1 answer
  • Which of the following best describes the graph shown below?
    15·1 answer
  • A rectangle has an area of 22.64 inches squared. If the coordinates of one of its sides are (0, 0) and (4, 4), what are the dime
    14·1 answer
  • Lisa's weekly pay increases from $525 to $546<br> Calculate her percentage pay increase.
    10·1 answer
  • I think of a number, halve it, than subtract four
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!