$y=2\sqrt[3]{x+2}\ \ \ |divide\ both\ sides\ by\ 2\\\\\sqrt[3]{x+2}=\dfrac{y}{2}\to x+2=\left(\frac{y}{2}\right)^3\ \ \ |subtract\ 2\ from\ both\ sides\\\\x=\dfrac{y^3}{2^3}-2\\\\x=\dfrac{1}{8}y^3-2\\\\\boxed{f(x)=2\sqrt[3]{x+2}\to f^{-1}(x)=\frac{1}{8}y^3-2}$

5 0

3 years ago

If you had to subtract 426 from 913, how many times would you need to regroup? how can you tell?

viktelen [127]

Regrouping in subtraction means that if you can't subtract because the digit on the bottom has a greater value than the digit on the top (such as 3-6)m so in this case you would have to regroup twice.

5 0

3 years ago

PLEASE PLEEASE HELP I PROMISE I WILL GIVE BRAINLIIEST!!!!

Nadusha1986 [10]

Answer:

76, the middle one

Step-by-step explanation:

6 0

3 years ago

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