This is the concept of algebra, we are required to calculate the area cut out of a cylinder represented by the function x^2+z^2=36;
The equation of a circle is given by:
(x-a)^2+(y-b)^2=r^2
where;
(a,b) are the center of the circle;
r=radius of the circle
re-writing our equation we have:
x^2+z^2=36
(x-0)^2+(z-0)^2=6^2
this implies that the center of the circle is (0,0) and the radius is 6 units;
Therefore the area will be given by:
Area=πr^2
Area=π*6^2
Area=36π=113.1 sq. units
Answer:
both A and B
Step-by-step explanation:
I hope that helps
Answer:
Do you want to know the surface area of the triangle or the perimeter of the triangle?
Step-by-step explanation:
If you are looking for the Surface area, plug your numbers in this formula: SA=(p x h)/(2) + B where SA is the surface area of the pyramid, p is the perimeter of the base, h is the slant height of the pyramid, and B is the area of the base.
Since AED forms a straight line, all involved angles sum to 180°. Therefore AEB + BED = 180. Also, since EC bisects BED, BEC = CED, and BED = 2× CED. Now to substitute the first equation:
AEB + BED = 180
AEB + 2×CED = 180
11x-12 + 2(4x+1) = 180
11x-12+8x+2 = 180
19x-10 = 180
19x-10+10 = 180+10
19x = 190
x = 10
So what is m<AEC?? It is the sum of AEB + BEC, and since BEC = CED we can say that:
AEC = AEB + CED
AEC = 11x-12 + 4x+1 = 15x-11 = 15(10)-11 = 150-11
m<AEC = 139°
