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3 years ago

Is the point 1,3 a solution to the linear equation 5x-9y=32

Mathematics

1 answer:

german3 years ago

3 0

No it is not. Substituting for x=1 and y=3 in the equation, you get 5x - 9y is 5 - 27 = -22

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What is the value of the digit 1 in the number 0.413

Akimi4 [234]

.01 is the answer to that or one one hundredth

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2 years ago

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I need help... I honestly don’t know.

Serhud [2]

Answer:

∡ABC=55°

Step-by-step explanation:

Step 1: Identify all angles

∠A=(x+45)°

∠B=(6x+5)°

∠C=(3x)°

∠ABC=(180-∠B)°=(180-(6x+5))°

Step 2: Use the Triangle Angle Sum Theorem

∠A+∠ABC+∠C=180°

(x+45)+(180-(6x+5))+(3x)=180

x+45+180-6x-5+3x=180

-2x+45+180-5=180

-2x+45-5=0

-2x+40=0

-2x=-40

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Step 3: Plug in x=20 for ∠ABC

∠ABC=(180-(6x+5))°

(180-6(20)-5)°

(180-120-5)°

(60-5)°

55°

So ∡ABC=55°

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2 years ago

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2 years ago

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2 years ago

Ab and bc form a right angle at point B. if a= (-3,-1) and B= (4,4) what is the equation of BC?

Vesnalui [34]

Answer:

Option C $-7x-5y=-48$

Step-by-step explanation:

step 1

Find the slope of AB

we have

A(-3,-1) and B(4,4)

The slope m is equal to

$m=(4+1)/(4+3)$

$m=5/7$

step 2

Find the slope of BC

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1

$m1*m2=-1$

we have

$m1=5/7$

substitute

$5/7*m2=-1$

$m2=-7/5$

step 3

Find the equation of the line into slope point form

$y-y1=m(x-x1)$

we have

$m=-7/5$

$B(4,4)$

substitute

$y-4=-(7/5)(x-4)$

Multiply by 5 both sides

$5y-20=-7x+28$

$7x+5y=28+20$

$7x+5y=48$

Multiply by -1 both sides

$-7x-5y=-48$

3 0

2 years ago